Lua++ example

// STL
#include <iostream>

// Lua
#include "Lua++.hpp"

using namespace std;

void PrintTable(Lua::Variable tbl, int depth = 0)
{
    for(auto pair : tbl.pairs())
    {
        for(int i = 0; i < depth; i++)
            cout << '\t';

        if(pair.second.GetType() == Lua::Type::Table)
        {
            cout << pair.first.ToString() << ":\n";
            return PrintTable(pair.second, depth + 1);
        }

        cout << pair.first.ToString() << " = " << pair.second.ToString() << "\n";
    }
}

list<Lua::Variable> TestFunc(Lua::State* state, list<Lua::Variable>& args)
{
    cout << "This is a test function, " << args.size() << " arguments provided, which are: \n";

    for(Lua::Variable& var : args)
    {
        if(var.GetType() == Lua::Type::Table)
        {
            cout << "\t" << var.GetTypeName() << ":\n";
            PrintTable(var, 2);
            continue;
        }
        cout << "\t" << var.GetTypeName() << ": " << var.ToString() << "\n";
    }

    return {};
}

int main(int argc, char** argv)
{
    using namespace Lua;

    try
    {
        State state;
        state.LoadStandardLibary();

        // Generate a Lua variable for our function
        Variable testfunc = state.GenerateFunction(TestFunc);
        // Set it as a global variable
        state["TestFunc"] = testfunc;

        // load and execute a file
        state.DoFile("test.lua");


        state["GiveMeAString"]("hello"); // call the function GiveMeAString, with the argument "Hello"
    }
    catch(Lua::Exception ex)
    {
        cout << "Lua exception: \n" << ex.what() << "\n";
        return 1;
    }

    return 0;
}