Python day 5

## List of list or nested list

persons = [["sam",45],["kevin",30],["john",20],["prince",25]]
for item in persons:
  name = item[0]
  age = item[1]
print(name, age)

### Unpacking second method

persons = ["sam",45]
name,age = persons
print(persons)

### Unpacking Third method

s1 = ["sam",25,"[email protected]"]
name,age,mail = s1
print(mail)

### Unpacking fourth method

s1 = ["sam",25,"[email protected]","AB+","9249282390"]
name,age,mail,*_ = s1
print(s1)

### Unpacking 5 method

s1 = ["sam",25,"[email protected]","AB+","9249282390"]
*_,mobile = s1
print(mobile)

persons = [["sam",20,"[email protected]"],["john", 28, "[email protected]"],["prince",20,"[email protected]"]]
search = input("Enter the person u want to search : ")
for item in persons:
  name = item[0]
  age = item[1]
  if name == search:
    print(name, "age is : ", age)


## Break

persons = [["sam",20,"[email protected]"],["john", 28, "[email protected]"],["prince",20,"[email protected]"]]
search = input("Enter the name of the person : ")
for item in persons:
  name = item[0]
  age = item[1]
  mail = item[2]
  if name == search:
    print("The", name,"details are", "Age:",age, "Maild_id: ", mail)
  else:
    print("Sorry no details fount")
  break


number = ["79345","4567","2345","8065","3218"]
for item in number:
  for x in item:
    if int(x) % 2 == 0:
      print(x)
      break


## Dictionary data type

persons = {"sam": 45, "kevin": 30, "prince": 20, "john":25}
x =  len(persons)
print(x)

persons = {"sam": 45, "kevin": 30, "prince": 20, "john":25}
print(persons["kevin"])

persons = {"sam": 45, "kevin": 30, "prince": 20, "john":25}
for item in persons:
  age = persons[item]
  print(item, age)

persons = {"sam": 45, "kevin": 30, "prince": 20, "john":25}
print("sam" in persons)

persons = {"sam": 45, "kevin": 30, "prince": 20, "john": 25, "jobin": 30 , "colombus": 30}
search = input("Enter the name of the employee to search the age: ")
if search in persons:
  print(persons[search])
else:
  prinT("Sorry no match found")


## Empty dit

students = {}
students["sam"] = "25000"
students["john"] = "30000"
students["kevin"] = "5000"
print(students)

## Value as list

persons = {"sam": [45,4500], "john": [50,50000], "prince": [60,6000]}
salary = persons['sam'][1]
print(salary)

## Value as dict

persons = {"sam": {"age": 45, "salary": 45000}, "john": {"age": 50 , "salary": 5000}, "prince": {"age": 60,"salary": 6000}}
print(persons['john']['salary'])


##------------------------------------- Task 2 -----------------------------------##

## 1] find the biggest number from the list.

l = [1, 4, 2, 9, 7]
y = 0

for item in l:
  x = int(item)
  if x > y:
    y = x
print(y)


## 2] find the smallest number from the list.

l = [1, 4, 2, 9, 7]
y = 1

for item in l:
  x = int(item)
  if x <= y:
    y = x
print(y)


## 3] find the sum of salaries.


persons = [ ["john",2400] , ["sam",2500] , ["teena",2210] , ["kevin",3400] , ["devon",1200] ]
y = 0
for item in persons:
  x = int(item[1])
  y = y + x
print(y)



## 4] add the names to employees list.

persons = [ ["john",20] , ["sam",25] , ["teena",22] , ["kevin",34] , ["devon",32] ]

employees = []

for item in persons:
  name = item[0]
  employees.append(name)
print(employees)

## 5] print all the words Starts With vowel chars "aeiou" append all word to mylist, avoid duplicate.

s = """The OS includes some common elastic core components, like the GNU tools,
among others. These kick tools give the user a way to manage the resources
provided by the kernel, Kernel apple install additional axe knee software, configure performance
and security Knife settings, and more. eye keep All of odd these tools bundled together
make up the knee umbrella keen axe functional kick operating system.  Because Linux is an open source
OS, combinations of kick elastic software enrich can vary between Linux distributions."""

mylist = []

s = s.replace('.','')
s = s.lower().replace(',','')
s = s.split()
for item in s:
  if item[0] in 'a,e,i,o,u':
    if item not in mylist:
      mylist.append(item)

print(mylist)

## 6]  add salary to salary list, salary list must be empty.

mydict = { "sam":50 , "alex":48 , "kevin":30 , "john":35 , "jane": 25 }

salary = []

for item in mydict:
  x = int(mydict[item])
  salary.append(x)
print(salary)

## 7] find the sum of salaries.

mydict = { "sam":50 , "alex":48 , "kevin":30 , "john":35 , "jane": 25 }
y = 0
for item in mydict:
  x = int(mydict[item])
  y = y + x
print(y)


## 8 ]  find the sum of salaries

mydict = { "sam":[50,5000] , "alex":[48,4800] , "kevin":[30,3000] , "john":[35,3500] , "jane":[25,2500] }
y = 0

for item in mydict:
  salary = mydict[item][1]
  y = y + salary
print(y)


## 9] create a list of list from mydict

mydict = { "sam":[50,5000] , "alex":[48,4800] , "kevin":[30,3000] , "john":[35,3500] , "jane":[25,2500] }

ll = []

for item in mydict:
  salary = mydict[item][1]
  ll.append(item)
  ll.append(salary)
print(ll)

## 10] find the total salary

mydict = {
           "sam":{ "age":50,"salary":5000},
           "alex":{ "age":48,"salary":4800},
           "kevin":{ "age":30,"salary":3000}
         }

y = 0
for item in mydict:
  x = int(mydict[item]['salary'])
  y = y + x
print(y)