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Jun 23rd, 2018
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MySQL 0.19 KB | None | 0 0
  1. $sql = "SELECT blog_posts.* ,
  2.                        users.username
  3.                 FROM blog_posts
  4.                 WHERE blog_posts.id = '{$inI}'
  5.                 INNER JOIN users ON (
  6.                 blog_posts.author_id = userID)";
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