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TimmyChannel

Python Alena

Feb 8th, 2024
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Python 0.37 KB | None | 0 0
  1. p = range(257,357)
  2. q = range(5,601)
  3. r = range(59,229)
  4. minA = 10**15
  5. for b in range(200):
  6.     for c in range(b, b+200):
  7.         a = range(b, c+1)
  8.         for x in range(1,500):
  9.             if not(((x in r)<=(x in a)) or (((x%3==0)<=(x in p))<=((x in q)<=(x in a)))):
  10.                 break
  11.         else:
  12.             minA = min(minA, c-b)
  13.            
  14. print(minA)
  15.  
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