ICPC - machine

#include <iostream>

using namespace std;

int main(){

    int x[5];
    int y[5];
    int counter = 0;
    while (cin >> x[0] >> x[1] >> x[2] >> x[3] >> x[4]){

        cin >> y[0] >> y[1] >> y[2] >> y[3] >> y[4];

        for (int k = 0;k < 5; k++){
            if (x[k] != y[k]){
                counter++;
            }else if (x[k] == y[k]){
                break;
            }

        }
        if (counter == 5){
            cout << "Y" << endl;
        }else {
            cout << "N" << endl;
        }
        counter = 0;
    }
}