vqrno reshenie na sleepy tom

function sleeppyTom(arg1) {
    let holidays = Number(arg1);
    let workingDays = 365 - holidays;
    let totalPlayMinutes = workingDays * 63 + holidays * 127;
    let difference = Math.abs(totalPlayMinutes - 30000);
    let hours = difference / 60;
    let minutes = difference % 60;

    if (totalPlayMinutes > 30000) {
        console.log(`Tom will run away`);
        console.log(`${Math.floor(hours)} hours and ${Math.floor(minutes)} minutes more play`);
    } else {
        console.log(`Tom sleeps well`);
        console.log(`${Math.floor(hours)} hours and ${Math.floor(minutes)} minutes less play`);
    }
}