#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include<math.h>
#include <smmintrin.h>

float dot_product(const float *A, const float *B, int startA, int endA, int startB, int endB){
        union {
         __m128 xmm;
        float f[4];
        } result;
        result.f[0] = 0.0;
        result.f[1] = 0.0;
        result.f[2] = 0.0;
        result.f[3] = 0.0;

        int i = startA;
        int t = startB;

    for ( i = startA; i + 3 < endA; i += 4) {

                union {
                float a[4];
                __m128 xmm;
                } value1;

                for(int  j = 0; j < 4; j++) {
                        value1.a[j] = A[i+j];
                }

                union {
                float a[4];
                __m128 xmm;
                } value2;

                for(int  j = 0; j < 4; j++) {
                        value2.a[j] = B[t+j];
                }
                __m128 val = _mm_dp_ps(value1.xmm, value2.xmm, 0xF1);
                 result.xmm = _mm_add_ss(result.xmm, val);
                t +=4;
        }
        double res = result.f[0];
        for (; i < endA; i++) {
                res += A[i]*B[t];
                t++;
        }
        return res;
}


 void multiply(float*A, float*B, float*res, int N, int M) {
         for (int i = 0; i < N; i++) {
                 for (int j = 0; j < N; j++) {
                        res[i*N+j] = dot_product(A, B, i*M, (i+1)*M, j*M, (j+1)*M);
                 }
         }
}
void Print(float* res, int N, int M) {
       for (int i = 0; i < N; i++) {
                 for (int j = 0; j < M; j++) {
                        printf("%f ", res[i*M + j]);
                 }
                 printf("\n");
         }
}

int main() {
        int N, M;
         scanf("%d %d", &N, &M); //N -количество строк, M - количество столбцов
         float *A = calloc(N*M, 4);
         float *B = calloc(N*M, 4);
         float *res = calloc(N*M, 4);
         for (int i = 0; i < N; i++) {
                 for (int j = 0; j < M; j++) {
                        scanf("%f", &A[i*M + j]);
                 }
         }
         for (int i = 0; i < M; i++) {
                 for (int j = 0; j < N; j++) {
                        scanf("%f", &B[j*M + i]);
                 }
         }
         multiply(A, B,res,  N, M);
         Print(res, N, N);
return 0;
}