timeit of a simple Python statement

''' timeit_lambda_simple101.py
using Python module timeit on a simple statement
(by default timeit turns off garbage collection)

if you have iPython running it is even simpler ...
In [1]: %timeit not 9999991 & 1
10000000 loops, best of 3: 39.9 ns per loop

In [2]: %timeit 9999991 % 2 == 0
10000000 loops, best of 3: 60 ns per loop
'''

import timeit

'''
# use n=1000000 passes (this is also the default)
# this way the result will be time per pass in microseconds
elapsed = lambda stmt, n=1000000: timeit.Timer(stmt).timeit(n)
'''

# or even simpler
# using default 1000000 passes --> micro-seconds/pass
elapsed = lambda stmt: timeit.Timer(stmt).timeit()

stmt = "x = (12345679 * 63)//7"
# run and show the timeit test
print("'%s' took %0.3f micro-seconds" % (stmt, elapsed(stmt)))

stmt = "not 9999991 & 1"  # True if even
# run and show the timeit test
print("'%s' took %0.3f micro-seconds" % (stmt, elapsed(stmt)))

stmt = "9999991 % 2 == 0"   # True if even
# run and show the timeit test
print("'%s' took %0.3f micro-seconds" % (stmt, elapsed(stmt)))

''' result (Python 3.4.1 64bit) -->
'x = (12345679 * 63)//7' took 0.022 micro-seconds
'not 9999991 & 1' took 0.033 micro-seconds
'9999991 % 2 == 0' took 0.054 micro-seconds
'''