27.01.2022

#1
a = int('1000100110101011', 2)
print(oct(a)[2:])

#2
print('С -', 10)
print('О - 010')
print('К -', 11)
print(1001011)

#1
def DEL(n, m):
    return n % m == 0

def f(x, A):
    return (not DEL(x, A)) <= (DEL(x, 6) <= (not DEL(x, 9)))

for A in range(1000, 0, -1):
    #print(A)
    true_is_A = True
    for x in range(1, 1000):
        if not f(x, A):
            true_is_A = False
    if true_is_A:
        print(A)
        break