H + OH = 1 * 10^-14
H = 1* 10^-14 + 1*10^6
H = 1 * 10 ^-8

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pH = - log H

pH = - log 1 * 10^-3

pH = 3

entonces es acida

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H + OH = 1 * 10^-14
H = 1* 10^-14 + 1*10^5
H = 1 * 10 ^-9

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14 - 8.42 = 5.58

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La logica de este es igualita al ejemplo
H+ = antilog -7.41 = 3.86 * 10 ^-8