double
mostIsolated(vector<double> & number)
{
	double MI, last1, next1, greatest;
	vector<double>::iterator iter = number.begin();
	while (next(iter, 1) != number.end())
	{
		if (iter == number.begin())
		{
			auto nxt = next(iter, 1);
			MI = *iter;
			greatest = *nxt - *iter;

		}
		else
		{
			vector<double>::iterator last = prev(iter, 1);
			vector<double>::iterator nxt = next(iter, 1);
			last1 = *iter - *last;
			next1 = *nxt - *iter;
			if (next1 > last1)
			{
				if (last1 > greatest)
				{
					MI = *iter;
					greatest = last1;

				}
			}
			else
			{
				if (next1 > greatest)
				{
					MI = *iter;
					greatest = next1;
				}
			}
		}
		iter++;
	}

	return MI;
}