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- Problem 1. Some Primes
- Find the 24th, 101st and 251st prime number.
- Solution:
- 24th prime number is 89
- 101st prime number is 547
- 251st prime number is 1597
- - Source for solution: http://www.wolframalpha.com/
- Problem 2. Some Fibonacci Primes
- Check if the 24th, 101st and 251st prime numbers are part of the base Fibonacci number set. What is their position?
- Solution:
- 24th prime number ( 89 ) is part of the base Fibonacci number set. Its position is: 11th
- 101st prime number is not part of the base Fibonacci number set;
- 251th prime number ( 1597 ) is part of the base Fibonacci number set. Its position is: 17th
- - Source for solution: http://www.wolframalpha.com/
- Problem 3. Some Factorials
- Find 100!, 171! and 250! Give all digits.
- Solution:
- 100! = 93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000
- 171! = 1241018070217667823424840524103103992616605577501693185388951803611996075221691752992751978120487585576464959501670387052809889858690710767331242032218484364310473577889968548278290754541561964852153468318044293239598173696899657235903947616152278558180061176365108428800000000000000000000000000000000000000000
- 250! =
- 3232856260909107732320814552024368470994843717673780666747942427112823747555111209488817915371028199450928507353189432926730931712808990822791030279071281921676527240189264733218041186261006832925365133678939089569935713530175040513178760077247933065402339006164825552248819436572586057399222641254832982204849137721776650641276858807153128978777672951913990844377478702589172973255150283241787320658188482062478582659808848825548800000000000000000000000000000000000000000000000000000000000000
- - Source for solution: http://www.wolframalpha.com/
- Problem 4. Calculate Hypotenuse
- You are given three right angled triangles. Find the length of their hypotenuses.
- 1. Catheti: 3 and 4
- Solution:
- Hypotenuses = √(32+42)= 5
- 2. Catheti: 10 and 12
- Solution:
- Hypotenuses = √(102+122)= 15.6204993518
- 3. Catheti 100 and 250
- Solution:
- Hypotenuses = √(1002+2502)= 269.258240357
- Problem 5. Numeral System Conversions
- Convert 1234d to binary and hexadecimal numeral systems.
- Solution:
- 1234d = 10011010010b=4D2hex
- Convert 1100101b to decimal and hexadecimal numeral systems.
- Solution:
- 1100101b=101d=65hex
- Convert ABChex to decimal and binary numeral systems.
- Solution:
- ABChex=2748d=101010111100b
- - Source for solution: Windows 7 - Calculator
- Problem 6. Least Common Multiple
- Find LCM(1234, 3456).
- Solution:
- LCM(1234, 3456) = 2 132 352
- - Source for solution: http://www.wolframalpha.com/
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