'use strict';

function getLargestBinaryGap(input) {
    var binary = (input >>> 0).toString(2);
    var longestGap = 0;
    var matchArray = [];
    var regexp = /1{1}(0+)(?=1)/g;

    while ((matchArray = regexp.exec(binary)) !== null) {
        let matchLength = matchArray[1].length;

        if (matchLength > longestGap) {
            longestGap = matchLength;
        }
    }

    return longestGap;
}

console.log(getLargestBinaryGap(6));
console.log(getLargestBinaryGap(1041));