1.account number
#include<stdio.h>
#include<conio.h>
int reg(int n, int a[], int c);
int main(){
	int n=0,num,a[30],i,flag=0,bcode=0;
	clrscr();
	printf("\nEnter the number of array elements:");
	scanf("%d",&n);
	if(n<0){
		printf("\nInvalid array size");
		}
		printf("\nenter the elements:");
	for(i=0;i<n;i++){
		scanf("%d",&a[i]);
		if(a[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("\nInvalid account number");

	}
	printf("\nenter the branch code to be verified");
	scanf("%d",&bcode);
	if(bcode<0){
		printf("\nInvalid branch code");
	}
	num=reg(n,a,bcode);
	printf("\nThe number of account numbers in that branch are%d",num);
	getch();
	return 0;
}
int reg(int n, int a[], int c){
	int i,temp,bcode=0,count=0;
	for(i=0;i<n;i++){
		temp=a[i];
		bcode=temp/100;
		if(bcode==c)
			count++;
	}
	return count;
}
2.average odd key values
#include<stdio.h>
#include<conio.h>
int avgoddkeyvalues(int a[],int n)
{
int count=0,sum=0,avg;
for(i=0;i<n;i+=2)
{
if(a[i]%2!=0)
{
sum=sum+(a[i+1]);
count++;
}
}
avg=sum/count;
return avg;
}
main()
{
int i,n,a[100],counter;
clrscr();
printf("\nenter the total num of values");
scanf("%d",&n);
printf("\nenter the array values:");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
counter=avgoddkeyvalues(int a[],int n);
printf("the average odd key values are %d",counter);
getch();
return 0;
}
3.product of maximum and minimum
#include<stdio.h>
#include<conio.h>
int promaxmin(int a[],int n)
{
int i,j,maxmin,temp;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(a[j]>a[j+1])
{
temp=a[j];
a[j]=a[j+1];
a[j+1]=temp;
}
}
}
maxmin=a[0]*a[n-1];
return maxmin;
}
main()
{
int n,a[100],i,pro;
clrscr();
printf("\nenter the number of inputs:");
scanf("%d",&n);
printf("\nenter the values one by one:");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
pro=promaxmin(a,n);
printf("\n%d is the values",pro);
getch();
return 0;
}
4.sum of prime numbers in the array
#include<stdio.h>
#include<conio.h>
void main()
{
int a[100],i,n,j,counter,sum=0;
clrscr();
printf("\nenter the no of elements:");
scanf("%d",&n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<n;i++)
{
counter=0;
for(j=2;j<a[i];j++)
{
if(a[i]%j==0)
{
counter=1;
break;
}
}
if(counter==0)
{
sum=sum+a[i];
}
}
printf("\n the sum of the prime numbers in the array is %d",sum);
getch();
}
5.average of prime index sum
#include<stdio.h>
#include<conio.h>
prime(int a[],int n)
{
int temp=0,counter=0,sum=0,i,j,avg;
for(i=2;i<=n;i++)
{
counter=0;
for(j=1;j<=i;j++)
{
if(i%j==0)
counter++;
}
if(counter==2)
{
sum=sum+a[i];
temp++;
}
else
continue;
}
avg=sum/temp;
return avg;
}

main()
{
int n,a[100],avg,i;
clrscr();
printf("\nenter the number of elements");
scanf("%d",&n);
printf("\nenter the number of elements one by one");
for(i=1;i<=n;i++)
{
scanf("%d",&a[i]);
}
avg=prime(a,n);
printf("\nthe prime index sum average is %d",avg);
getch();
return 0;
}
31.sumPrimeArray
Read the question carefully and follow the input and output format.

John is working in a bank. He has created account details transaction in a file and protected it with a password. He sent the file to his manager for review. The file is protected with a password. The password is the sum of Prime numbers. Write a function to generate the password.

Input and Output Format:
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the sum.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.
3) Print 0, when there are no prime numbers in a given input array.

Include a function named sumPrimeArray(int array[], int size) whose return type is an integer, which is the prime sum.

Sample Input 1:
5
1
2
3
4
5

Sample Output 1:
10

Sample Input 2:
3
4
8
9

Sample Output 2:
0
#include<stdio.h>
#include<stdlib.h>
int sumPrimeArray(int array[], int size);
int main(){
	int n=0,flag=0,i,input[20],sum=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}

	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	sum = sumPrimeArray(input,n);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int sumPrimeArray(int array[],int n){
	int sum=0,i=0,j,count=0;
	for(i=0;i<n;i++){
		count=0;
		for(j=1;j<=array[i];j++){
			if(array[i]%j==0)
				count++;
		}
		if(count==2)
			sum=sum+(array[i]);
	}
	return sum;
}
32. avgOddKeyValues
Read the question carefully and follow the input and output format.


Given an input array, First index represents key and second index represents the value and so on... Write code to find out the average of all values whose keys are odd numbers.

Input and Output Format :
First line of input consists of n, the next n lines correspond to the elements of the array. Output consist of the an integer.

Print "Invalid array size" when size of the array is a negative number and terminate the program.
Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named avgOddKeyValues(int numbers[], int size) whose return type is an integer.

Sample Input 1:
8
1
3
2
4
3
16
4
25
Sample Output 1:
9

Sample Input 2:
-3
Sample Output 2:
Invalid array size
#include<stdio.h>
#include<stdlib.h>

int avgOddKeyValues(int numbers[], int size);
int main(){
	int n=0,avg=0,input[30],i,flag=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	avg = avgOddKeyValues(input,n);
	printf("%d",avg);
	getchar();
	getchar();
	return 0;
}
int avgOddKeyValues(int numbers[], int size){
	int i,j=0,avg=0,sum=0;
	for(i=0;i<size;i=i+2){
		if(numbers[i]%2!=0){
			sum=sum+numbers[i+1];
			j++;
		}
	}
	avg = sum/j;
	return avg;
}
33.Product of MaxMin Element

Write a program to find the product of the maximum and minimum element in a given input array.

Include a function named productOfMaxMin that accepts 2 arguments and returns an int. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns an int that corresponds to the product of maximum and minimum element.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer that corresponds to the product of maximum and minimum element in the array.
Assume that the maximum number of elements in the array is 20.

Sample Input 1:
8
2
12
3
4
6
8
10
9

Sample Output 1:
24

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-200

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>

int productOfMaxMin(int numbers[], int size);
int main(){
	int n=0,product=0,input[30],i,flag=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	product = productOfMaxMin(input,n);
	printf("%d",product);
	getchar();
	getchar();
	return 0;
}
int productOfMaxMin(int numbers[], int size){
	int i,j=0,prod=0,temp=0;
	for(i=0;i<size;i++){
		for(j=i+1;j<size;j++){
			if(numbers[i]<numbers[j]){
				temp = numbers[j];
				numbers[j] = numbers[i];
				numbers[i] = temp;
			}
		}
	}
	prod = numbers[0] * numbers[size-1];
	return prod;
}
34.registerAccountNumbers

Read the question carefully and follow the input and output format.

Given an array in which the elements are in xxxyy format, where first xxx digits represent the Branch code and the yy represents the account
id.  Find out the No of accounts in the given branch code

Input and Output Format :
The first input n corresponds to the size of the array, the next n lines correspond to the elements of the array and the last line of the input corresponds to the branch code.
Output corresponds to the number of accounts in the given branch code
If the given branch code is not available, print 0.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program
2) Print "Invalid account Number" when there is any negative number available in the input array and terminate the program
3) Print "Invalid branch code" when branch code is negative number and terminate the program

Include a function named registerAccountNumbers (int size, int account_numbers[], int branch_code) that returns the no of accounts

Sample Input 1 :
6
12345
12370
12324
13355
13333
14575
123

Sample Output 1 :
3

Sample Input 2 :
-6

Sample Output 2:
Invalid array size
     #include<stdio.h>
#include<stdlib.h>
int registerAccountNumbers (int size, int account_numbers[], int branch_code);
int main(){
	int n=0,no_of_acc=0,input[30],i,flag=0,bcode=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid account number");
		getchar();
		getchar();
		exit(0);
	}
	scanf("%d",&bcode);
	if(bcode<0){
		printf("Invalid branch code");
		getchar();
		getchar();
		exit(0);
	}
	no_of_acc=registerAccountNumbers(n,input,bcode);
	printf("%d",no_of_acc);
	getchar();
	getchar();
	return 0;
}
int registerAccountNumbers(int size, int account_numbers[], int branch_code){
	int count=0,i,rem,temp=0,k=1,bcode=0,x=1;
	for(i=0;i<size;i++){
		temp=account_numbers[i];
		bcode=temp/100;
		if(bcode==branch_code)
			count++;
	}
	return count;
}
35.newArraySum
Read the question carefully and follow the input and output format.

Given an input array which contains age of some employees, write a program t fund the sum of ages of employees greater than 18.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the sum.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named newArraySum(int age[],int size) whose return type is an integer, which is the sum.

Sample Input 1:
5
21
22
17
10
25
Sample Output 1:
68

Sample Input 2:
6
50
-36

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int newArraySum(int age[],int size);
int main(){
	int n=0,sum=0,input[30],i,flag=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	sum = newArraySum(input,n);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int newArraySum(int age[],int size) {
	int i=0,sum=0;
	for(i=0;i<size;i++){
		if(age[i]>18)
			sum=sum+age[i];
	}
	return sum;
}
36.Array Product

Write a program to find the product of posive/nonnegative elements in a given array.

Include a function named calculateProduct that accepts 2 arguments and returns an int. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns an int that corresponds to the product.

If the size of the array is negative or if it is greater than 10 or if any element in the array is more than 2 digits, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer that corresponds to the product of positive numbers in the array.

Sample Input 1:
8
1
-2
3
4
-6
8
10
-6

Sample Output 1:
960

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
200

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int calculateProduct(int[],int);
int main(){
	int n=0,prod=0,input[30],i,flag=0;
	scanf("%d",&n);
	if(n<0 || n>10 ){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]>=100 || input[i]<=-100)
			flag=1;
	}
	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	prod = calculateProduct(input,n);
	printf("%d",prod);
	getchar();
	getchar();
	return 0;
}
int calculateProduct(int number[],int size) {
	int i=0,prod=1;
	for(i=0;i<size;i++){
		if(number[i]>0)
			prod=prod*number[i];
	}
	return prod;
}




37.Perfect Number

Write a program to find whether the given number is a perfect Number.

A number is a perfect number if the sum of the proper divisors of the number is equal to the number itself.

Include a function named findPerfect that accepts an integer argument and returns an integer. The function returns
1.	1 if the input is a Perfect Number
2.	0 if the input is not a Perfect Number
3.	-1 if the input is a negative number or if it is greater than 32767

Input and Output Format:
Input consists of a single integer.
Output consists of a string.
Refer sample output for formatting specifications.


Sample Input 1:
6

Sample Output 1:
yes

Sample Input 2:
241

Sample Output 2:
no

Sample Input 3:
-9

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int findPerfect(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = findPerfect(number);
	if(result==1)
		printf("yes");
	else if(result==0)
		printf("no");
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int findPerfect(int n){
	int res=0,i,sum=0;
	if(n<0 || n>32767)
		res = -1;
	else{
		for(i=1;i<n;i++){
			if(n%i==0)
				sum=sum+i;
		}
		if(sum==n)
			res = 1;
		else
			res=0;
	}
	return res;
}

38.Squares of Even Digits

Write a program to find the sum of the squares of even digits in a number.

Include a function named sumSquareEven that accepts an integer argument and returns an integer . The function returns -1 if the number is less than zero or if the number is greater than 32767.

Print Invalid Input if the function returns -1.

Input and Output Format:

Input consists of an integer.
Output consists of an integer.
Refer sample output for formatting specifications.

Sample Input 1:
3487

Sample Ouput 1:
80

Sample Input 2:
-8

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int sumSquareEven(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = sumSquareEven(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int sumSquareEven(int n){
	int res=0,i,rem=0;
	if(n<0 || n>32767)
		res = -1;
	else{
		while(n!=0){
			rem=n%10;
			if(rem%2==0)
				res=res+(rem*rem);
			n=n/10;
		}
	}
	return res;
}
39.sumPrimeArray
Read the question carefully and follow the input and output format.

John is working in a bank. He has created account details transaction in a file and protected it with a password. He sent the file to his manager for review. The file is protected with a password. The password is the sum of Prime numbers. Write a function to generate the password.

Input and Output Format:
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the sum.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.
3) Print 0, when there are no prime numbers in a given input array.

Include a function named sumPrimeArray(int array[], int size) whose return type is an integer, which is the prime sum.

Sample Input 1:
5
1
2
3
4
5

Sample Output 1:
10

Sample Input 2:
3
4
8
9

Sample Output 2:
0

#include<stdio.h>
#include<stdlib.h>
int sumPrimeArray(int array[], int size);
int main(){
	int n=0,flag=0,i,input[20],sum=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}

	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	sum = sumPrimeArray(input,n);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int sumPrimeArray(int array[],int n){
	int sum=0,i=0,j,count=0;
	for(i=0;i<n;i++){
		count=0;
		for(j=1;j<=array[i];j++){
			if(array[i]%j==0)
				count++;
		}
		if(count==2)
			sum=sum+(array[i]);
	}
	return sum;
}
40. Array Multiplication in Reverse

A company wanted to know the reward points of the employee so that at the end of every month they will credit some amount along with their salary. Each employee has 2 separate lists, in first list records will be sorted in employee’s employee number in ascending order. Second list records will be sorted in employee’s employee number in descending order. Hence the management has decided to multiply both the reward points and credit the amount based on the points. Here they followed the formula for multiplying the first entry value in the first list with the last entry value in the second list and second entry from the first list with the second last record from the second list. Repeat the same for all the entries in the lists.

Include a function named arrayProduct that accepts 3 arguments and ints return type is void. The first argument is the input array 1, the second argument is  the input array 2 and the third argument is an int that corresponds to the size of the array. The output array is stored in a global variable named output1.

If the size of the array is negative or if any element in any of the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of utmost 2n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the first array. The last 'n' integers correspond to the elements in the second array. If any of the inputs are invalid, then terminate the program.

Output consists of n integers that correspond to the elements in the result array.

Assume that the maximum size of the array is 20.

Sample Input 1 :
5
23
2
5
32
76
2
2
21
42
4

Sample Output 1 :
92
84
105
64
152

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int output1[20];
void arrayProduct(int[],int[],int);
int main(){
	int size=0,input1[20],input2[20],i=0;
	int flag1=0,flag2=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0)
			flag1=1;
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0)
			flag2=1;
	}
	if(flag1==1 || flag2==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	arrayProduct(input1,input2,size);

	return 0;
}
void arrayProduct(int ar1[],int ar2[],int size){
	int i=0,j=0,k=0;
	for(i=0,j=size-1;i<size&&j>=0;i++,j--){
		output1[i] = ar1[i]*ar2[j];
		printf("%d\n",output1[i]);
	}
	getchar();
	getchar();
}
41.University Type

Write a program to find if the student is eligible for first, second or third grade universities by finding the average of their marks given in the input integer array.

Grade should be calculated as given below :
Average >80 First Grade University
Average >60 Second Grade University
Otherwise Third Grade University

Include a function named calculateGrade that accepts 2 arguments and returns an integer. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns an integer that corresponds to the university type. The function returns 1 if the student is eligible for First Grade univesity, returns 2 if the student is eligible for Second Grade University, returns 3 if the student is eligible for Third Grade University and returns -1 if the average is greater than 99.

If the size of the array is negative or if any element in the array is negative or if the average marks scored by the student is greater than 99 , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of a string --- “First Grade University” or “Second Grade University” or “Third Grade University” or “Invalid Input”.
Assume that the maximum size of the array is 20.

Sample Input 1:
5
92
87
78
74
80

Sample Output 1:
First Grade University

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int calculateGrade(int[],int);
int main(){
	int n=0,input[30],i,flag=0,grade=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	grade=calculateGrade(input,n);
	if(grade==-1)
		printf("Invalid Input");
	else if(grade==1)
		printf("First Grade University");
	else if(grade==2)
		printf("Second Grade University");
	else if(grade==3)
		printf("Third Grade University");
	else
		;
	getchar();
	getchar();
	return 0;
}

int calculateGrade(int array[],int n){
	int grade=0,i,sum=0,avg=0;
	for(i=0;i<n;i++)
		sum=sum+array[i];
	avg=sum/n;
	if(avg>99)
		grade=-1;
	else if(avg>80)
		grade=1;
	else if(avg>60)
		grade=2;
	else
		grade=3;
	return grade;
}
42.Interchange Array

Write a program to interchange the first element in the array with the last element in the array. Repeat the process till the middle of the array.

Include a function named interchangeArray that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of the interchanged array.
Assume that the maximum number of elements in the array is 20.

Sample Input 1:
4
2
1
3
4

Sample Output 1:
4
3
1
2

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-200

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
void interchangeArray(int[],int);
int main(){
	int n=0,input[30],i,flag=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	interchangeArray(input,n);
	return 0;
}

void interchangeArray(int array[],int n){
	int i=0,temp=0,j;
	for(i=0,j=n-1;i<n/2;i++,j--){
		temp = array[i];
		array[i] = array[j];
		array[j] = temp;
	}
	for(i=0;i<n;i++)
		printf("%d\n",array[i]);
	getchar();
	getchar();
}
43.Armstrong Number

Write a program to find whether the given input number is an Armstrong Number.

Include a function named checkArmstrong that accepts an integer and returns an integer. The function returns
1.	yes if the input is an Armstrong number
2.	no if the input is not an Arnstrong number
3.	Invalid Input if the input is a negative number or if the input is not a 3-digit number.

Print Invalid Input if the function returns -1.

Input and Output Format:
Input consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
153

Sample Output 1:
yes

Sample Input 2:
161

Sample Output 2:
no

Sample Input 3:
2345

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int checkArmstrong(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = checkArmstrong(number);
	if(result==1)
		printf("yes");
	else if(result==0)
		printf("no");
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int checkArmstrong(int n){
	int res=0,temp=0,rem=0,sum=0;
	if(n<0 || n>999)
		res=-1;
	else{
		 temp = n;
		 while (temp != 0) {
			 rem = temp%10;
			 sum = sum + (rem*rem*rem);
			 temp = temp/10;
		 }
		 if (n == sum)
			 res=1;
		 else
			 res=0;
	}
	return res;
}

44.Factorial

Write a program to find the factorial of a given number.

Include a function named findFactorial that accepts an integer argument and returns an integer that corresponds to factorial. If the input value is negative or greater than 10, the function returns -1.

If the function returns -1, print Invalid Input.

Input and Output Format:
Input consists of a single integer.
Output consists of an integer.
Refer sample output for formatting specifications.


Sample Input 1:
4

Sample Output 1:
24

Sample Input 2:
-67

Sample Output 2:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int findFactorial(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = findFactorial(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int findFactorial(int n){
	int res=1,i;
	if(n<0 && n>10)
		res=-1;
	else{
		for(i=1;i<=n;i++)
			res = res * i;
	}
	return res;
}
45.Salary Calculation
Jim got his salary. His salary calculations are as follows.
From his Basic amount he gets 50% of his basic for house Rent allowances and 75% of his basic as special allowances . If the number of days he worked is 31 he gets 500 extra. Write a program to calculate his gross salary after calculating all his salary split up.

Include a function named calculateGross that accepts 2 integer arguments and returns a float. The first integer corresponds to Jim's basic salary and the second integer corresponds to the number of days Jim has worked. The function returns a float that corresponds to the gross salary.

Print Invalid Input and terminate the program in the following cases:
1.	Basic salary is greater than 10000
2.	Number of working days is greater than 31
3.	Basic salary is negative
4.	Number of working days is 0 or negative

Input and Output Format:
Input consists of 2 integers. The first integer corresponds to Jim's basic salary and the second integer corresponds to the number of days he has worked.
Output consists of a single float that corresponds to Jim's gross salary. The gross salary is displayed correct to 2 decimal places.

Sample Input 1:
5000
30

Sample Output 1:
11250 .00


Sample Input 2:
5000
0

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
float calculateGross(int,int);
int main(){
	int basic=0,days=0;
	float gross=0.0f;
	scanf("%d%d",&basic,&days);
	if(basic>10000 || days>31 || basic<0 || days==0 || days<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	gross = calculateGross(basic,days);
	printf("%0.2f",gross);
	getchar();
	getchar();
	return 0;
}

float calculateGross(int basic,int days){
	float salary=0.0f;
	if(days==31)
		salary=(float)(basic*50)/100+(float)(basic*75)/100+basic+500;
	else
		salary=(float)(basic*50)/100+(float)(basic*75)/100+basic;
	return salary;
}
46.Perfect Square

Write a program to find whether the given input number is a perfect square without using sqrt function.

Include a function named checkPerfectSquare that accepts an integer and returns an integer. The function returns
1.	1 if the input is a perfect square
2.	0 if the input is not a perfect square
3.	-1 if the input is a negative number

Print Invalid Input if the function returns -1.

Input and Output Format:
Input consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
36

Sample Output 1:
yes

Sample Input 2:
40

Sample Output 2:
no

Sample Input 3:
-2345

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int checkPerfectSquare(int);
int main(){
	int number=0,res=0;
	scanf("%d",&number);
	res = checkPerfectSquare(number);
	if(res==1)
		printf("yes");
	else if(res==0)
		printf("no");
	else
		printf("invalid Input");
	getchar();
	getchar();
	return 0;
}

int checkPerfectSquare(int n){
	if(n<0)
		return -1;
	else{
	while (((n % 2) == 0) && n > 1)
		n /= 2;
	return (n == 1);
	}
}
47.Find Index

Write a program to find the index of a particular number in a given input array.

Include a function named findIndex that accepts 3 arguments and returns an int. The first argument is the input array, the second argument is an int that corresponds to the size of the array and the third argument is the element to be searched for. The function returns the corresponding index if the search element is present in the array and returns -1 if the search element is not present in the array.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.


Input and Output Format:
Input consists of n+2 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array. The last integer corresponds to the element whose count needs to be found.
Output consists of an integer that corresponds to the index of the search element if it is present.
Else, print 'not found'.

Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20 and that all elements in the array are unique.

Sample Input 1:
8
2
1
3
8
6
12
10
19
8

Sample Output 1:
3

Sample Input 2:
8
2
1
3
8
6
12
10
19
80

Sample Output 2:
not found

Sample Input 3:
-5

Sample Output 3:
Invalid Input

Sample Input 4:
5
23
2
-200

Sample Output 4:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int cricketer[20];
int findIndex(int,int[],int);
int main(){
	int n=0,index=0,input[30],i,search_element=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
	}
	}
		scanf("%d",&search_element);
		index = findIndex(n,input,search_element);
			if(index==-1)
				printf("not found");
			else
				printf("%d",index);
		getchar();
		getchar();
		return 0;
}
	int findIndex( int size,int array[], int search){
	int index,i,f=0;
	for(i=1 ; i<size ; i=i+2)
	{
		if(array[i]==search){
			f=1;
			index = array[i-1];
			break;
		}
	}
	if(f==1)
		return index;
	else
		return -1;
}
48.Descending Order Sort

Write a program to sort the given array in descending order.

Include a function named sortArray that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array .

If the size of the array is negative or if any of the elements in the array are negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer array.
Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20.

Sample Input 1:
8
1
6
3
5
8
10
4
9


Sample Output 1:
10
9
8
6
5
4
3
1

Sample Input 2:
-5

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>

void sortArray(int numbers[], int size);
int main(){
	int n=0,input[20],i;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}

	sortArray(input,n);
	return 0;
}
void sortArray(int numbers[], int size){
	int i,j,temp=0;
	for(i=0 ; i<size ; i++){
		for(j=i+1 ; j<size ; j++){
			if(numbers[i]<numbers[j]){
				temp = numbers[i];
				numbers[i] = numbers[j];
				numbers[j] = temp;
			}
		}
	}
	for(i=0 ; i<size ; i++)
		printf("%d\n",numbers[i]);
	getchar();
	getchar();

}
49.endWithThree

Read the question carefully and follow the input and output format.

Given an input array, Find out the count of numbers that ends with 3.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of the count of numbers that ends with 3.

Print "Invalid array size" when size of the array is a negative number and terminate the program
Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named endWithThree(int numbers[], int size) whose return type is integer.

Sample Input 1:
5
23
353
33
12
14
Sample Output 1:
3

Sample Input 2:
5
1
7
3
-8
Sample Output  2:
Invalid input

#include<stdio.h>
#include<stdlib.h>

int endWithThree(int numbers[], int size);
int main(){
	int n=0,input[20],i,count=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}

	count = endWithThree(input,n);
	printf("%d",count);
	getchar();
	getchar();
	return 0;
}
int endWithThree(int numbers[], int size){
	int count=0,i,temp,rem=0;
	for(i=0 ; i<size ; i++){
		temp = numbers[i];
		rem = temp%10;
		if(rem==3)
			count++;
	}
	return count;

}
50.feeCalculation
Read the question carefully and follow the input and output format.

Student Fees is calculated according to the student's 10th marks. The student will get discount in fees as follows :

Marks discount(%)
>90         -  50%
81-90      - 25%
70-80      - 10%
<70         -  0%
Calculate the fees according to above table.

Note:
Formula : fees - (fees* discount(%))

Include a function named feeCalculation(int fee,int marks) that returns an integer that corresponds to the fee to be paid.


Print "Invalid mark" if the mark is greater than 100
Print "Invalid fee" if the fee is greater than 32767
Print "Invalid input" if any of the input is negative

Input and Output Format :
First line of input represents the fee, second line of input represents the marks of student.

Sample Input 1:
10000
95
Sample Output 1:
5000

Sample Input 2:
15896
101
Sample Output 2:
Invalid mark

#include<stdio.h>
#include<stdlib.h>

int feeCalculation(int fee,int marks);
int main(){
	int fees,mark,final_fee=0;
	scanf("%d",&fees);
	scanf("%d",&mark);
	if(mark>100)
		printf("Invalid mark");
	else if(fees>32767)
		printf("Invalid fees");
	else if(mark<0 || fees<0)
		printf("Invalid input");
	else{
	final_fee = feeCalculation(fees,mark);
	printf("%d",final_fee);
	}
	getchar();
	getchar();
	return 0;
}
int feeCalculation(int fee,int marks){
	int fee_final=0;
	float discount=0.0f;
	if(marks>90)
		discount = .50;
	else if(marks>80 && marks<=90)
		discount = .25;
	else if(marks>=70 && marks<=80)
		discount = .10;
	else
		discount = 0;
	fee_final = fee-(fee*discount);
	return fee_final;
}
51.sumTwoFive
Read the question carefully and follow the input and output format.

Given an integer array find the sum of elements which end with 2 or 5.

Input and Output Format:
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, the sum.

1) Print "Invalid array size" when size of the array is negative .
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named sumTwoFive(int array[], int size) whose return type is an integer, the sum

Sample Input 1:
5
22
35
5
2
10

Sample Output 1:
64

Sample Input 2:
-6

Sample Output 2:
Invalid array size


#include<stdio.h>
#include<stdlib.h>

int sumTwoFive(int array[], int size);
int main(){
	int n=0,input[20],i,sum=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}

	sum = sumTwoFive(input,n);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int sumTwoFive(int array[], int size){
	int i,rem,temp,sum=0;
	for(i=0;i<size;i++){
		temp = array[i];
		rem = temp % 10;
		if(rem==2 || rem==5)
			sum = sum+array[i];
	}
	return sum;
}
52.Sum of Odd Digits

Write a program to find the sum of the odd digits in a number.

Include a function named sumOddDigits that accepts an integer argument and returns an integer that corresponds to the sum of the odd digits. The function returns -1 if the input is less than zero or if it is greater than 32767.

If the function returns -1, print “Invalid Input”.

Input and Output Format:

The input consists of an integer.
The output consists of an integer that corresponds to the sum of the odd digits in the number.

Sample Input 1:
3487

Sample Ouput 1:
10

Sample Input 2:
-8

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int sumOddDigits(int);
int main(){
	int num=0,res=0;
	scanf("%d",&num);
	res = sumOddDigits(num);
	if(res==-1)
		printf("Invalid input");
	else
		printf("%d",res);
	getchar();
	getchar();
	return 0;
}
int sumOddDigits(int number){
	int sum=0,rem=0;
	if(number<0 || number>32767)
		sum=-1;
	else{
		while(number!=0){
			rem=number%10;
			if(rem%2!=0)
				sum=sum+rem;
			number=number/10;
		}
	}
	return sum;
}


53.LCM

Write a program to calculate the LCM of the 2 given integers.

Include a function named calculateLCM that accepts 2 integer arguments and returns an int that corresponds to the LCM of the 2 numbers.

Print Invalid Input and terminate the program in the following cases:
1.	Any of the 2 inputs is greater than 1000
2.	Any of the 2 inputs is negative


Input and Output Format:
Input consists of 2 integers.
Output consists of a single integer that corresponds to the LCM.

Sample Input 1:
10
8

Sample Output 1:
40


Sample Input 2:
50000


Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
#include<string>
int calculateLCM(int,int);
int main(){
	int a,b,res=0;
	scanf("%d%d",&a,&b);
	if(a>1000 || b>1000 || a<0 || b<0)
	{
		printf("Invalid input");
		exit(0);
		getchar();
		getchar();

	}
	res=calculateLCM(a,b);
	printf("%d",res);
	getchar();
	getchar();
	return 0;
}
int calculateLCM(int num1,int num2){
	int max=0;
	max=(num1>num2) ? num1 : num2;
	while(1){
			 if(max%num1==0 && max%num2==0){
				 break;
			}
			 ++max;
	 }

	return max;
}


54.Product of Prime Digits

Write a program to find the product of the prime digits in the given input number.

Include a function named productPrimeDigits that accepts an integer argument and returns an integer that corresponds to the product of the prime digits in the integer.
The function returns -1 if the input number is negative or greater than 32767.

If the function returns -1, print Invalid Input.

Please note that 1 and 0 are neiher prime nor composite.

Input and Output Format:
Input consists of an integer.
Output consists of an integer.
Refer sample output for formatting specifications.


Sample Input 1:
324


Sample Output 1:
6

Sample Input 2:
-67

Sample Output 2:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
#include<string>
int productPrimeDigits(int);
int main(){
	int digit=0,product=0;
	scanf("%d",&digit);
	product=productPrimeDigits(digit);
	if(product==-1)
		printf("Invalid input");
	else
		printf("%d",product);
	getchar();
	getchar();
	return 0;
}
int productPrimeDigits(int number){
	int prod=1,rem=0,i,count=0,flag=0;
	if(number<0 || number>32767)
		prod = -1;
	else
	{
		while(number!=0){
		rem=number%10;
		count=0;
		for(i=1;i<=rem;i++){
			if(rem%i==0)
				count++;
		}
		if(count==2){
			flag=1;
			prod = prod*rem;
		}
		number=number/10;
		}
	if(flag==0)
	prod = 0;
	}
	return prod;
}

55.dailyAllowance
Read the question carefully and follow the input and output format.

A Sales person daily allowances calculated as follows .
Item              Money (rupees)
Shirt                   15
Saree                 10
other items          5

Given an input array in which the first index represents no.of shirts sold, second index represents the no of sarees sold  and the third index represents the other items sold for a particular day, Calculate the total allowances.

Inlcude a function named dailyAllowance(int items[], int size) that returns an integer, which is the total allowances.

Business Rules:
1) Print "Invalid array size" when size of the array is a negative number and terminate the program
2) Print "Invalid item count" when there is any negative numbers available in the input array and terminate the program
3) Print "Array size greater than 3"  when size of the array is greater than 3 and terminate the program.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of the total allowance.

Sample Input 1:
3
10
5
10
Sample Output 1:
250

Sample Input 2:
4

Sample Output 2:
Array size greater than 3
#include<stdio.h>
#include<stdlib.h>

int dailyAllowance(int items[], int size);
int main(){
	int n=0,input[20],i,allowance=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	if(n>3){
		printf("Array size greater than 3");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid item count");
			getchar();
			getchar();
			exit(0);
		}
	}



	allowance  =  dailyAllowance(input,n);
	printf("%d",allowance);
	getchar();
	getchar();
	return 0;
}
int dailyAllowance(int items[], int size){
	int shirt=15,saree=10,other=5,allowance=0;
	allowance = (items[0]*shirt) + (items[1]*saree) + (items[2]*other);
	return allowance;
}
56.generateNumber


Read the question carefully and follow the input and output format.

Given an input number keep the prime digits as it is and the remaining digit in given input number should be replaced with next number(add +1 to the digit).

Print "Number too small" if the number is less than 0
Print "Number too large" if the number is greater than 32767
note : If any digit in the given input is 9 replace with 0. Consider 1 is not a prime number.

Include a function generateNumber(int number) that returns the generated number

Input and Output Format :
Input is a single integer.
Output is the generated number

Sample Input 1:
6234

Sample Output 1:
7235

Sample Input 2:
32768

Sample Output 2:
Number too large
#include<stdio.h>
#include<stdlib.h>

int generateNumber(int number);
int main(){
	int num=0,res=0;
	scanf("%d",&num);
	if(num<0)
		printf("number too small");
	else if(num>32767)
		printf("number too large");
	else
	{
		res = generateNumber(num);
		printf("%d",res);
	}
	getchar();
	getchar();
	return 0;
}
int generateNumber(int number){
	int rem=0,res=0,i=1;
	while(number!=0){
		rem=number%10;
		if(rem==2 || rem==3 || rem==5 || rem==7){
			res=res+(rem*i);
			i=i*10;
		}
		else if(rem==9){
			res=res+0;
			i=i*10;
		}
		else{
			res=res+((rem+1)*i);
			i=i*10;
		}
		number = number/10;
	}
	return res;
}
57.sortCommonElements

Read the question carefully and follow the input and output format.

Find out the common elements in the given input arrays and sort the common elements in ascending order.

Input and Output Format :
First line corresponds to n, the size of the array. The next n lines correspond to elements in the first array. The next n lines correspond to the elements in the second array. Output corresponds to the common elements sorted in ascending order.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program

Include a function named sortCommonElements(int set1[],int set2[],int size) whose return type is void.
The output array is stored in a global variable named common.

Sample Input 1:
5
1
3
2
5
7
4
5
6
7
2

Sample Output 1:
2
5
7

Sample Input 2:
5
5
8
-9

Sample Output 2:
Invalid input

Sample Input 3:
-4

Sample Output 3:
Invalid array size
#include<stdio.h>
#include<stdlib.h>
int common[20];
void sortCommonElements(int set1[],int set2[],int size);
int main(){
	int size=0,input1[20],input2[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	sortCommonElements(input1,input2,size);
	return 0;
}
void sortCommonElements(int set1[],int set2[],int size){
	int i=0,j=0,k=0,temp=0;
	for(i=0;i<size;i++){
		for(j=0;j<size;j++){
			if(set1[i]==set2[j]){
				common[k]=set1[i];
				k++;
			}
		}
	}
	/* Sorting elements */
	for(i=0;i<k;i++){
		for(j=i+1;j<k;j++){
			if(common[i]>common[j]){
				temp = common[i];
				common[i] = common[j];
				common[j] = temp;
			}
		}
	}
	for(i=0;i<k;i++)
		printf("%d\n",common[i]);
	getchar();
	getchar();
}
58.findEmployeeID
Read the question carefully and follow the input and output format.

In a given input array, elements are given in this Format PPPII, where PPP represents the Project Code and II represents employee id . Find out the Employee Ids who are working in the given project code.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements.  The next line corresponds to the project code. Output consists of the employee id's.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program
2) Print "Invalid employee id" when there is any negative numbers available in the input array and terminate the program
3) Print "Invalid project code" when branch code is negative number and terminate the program

Include a function named findEmployeeID(int size,int employee_ids[],int project_code). Its return type is void.
The output array is stored in a global variable named working_employee.

Sample Input 1:
5
12345
12334
23457
23478
12546
123
Sample Output 1:
45
34

Sample Input 2:
5
12345
12334
23457
-23478
Sample Output 2:
Invalid employee id
#include<stdio.h>
#include<stdlib.h>
int working_employee[10];
void findEmployeeID(int size,int employee_ids[],int project_code);
int main(){
	int n=0,input[30],i,pcode=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid employee id");
		getchar();
		getchar();
		exit(0);
		}

	}
	scanf("%d",&pcode);
	if(pcode<0){
		printf("Invalid project code");
		getchar();
		getchar();
		exit(0);
	}
	findEmployeeID(n,input,pcode);

	return 0;
}
void findEmployeeID(int size,int employee_ids[],int project_code){
	int count=0,i,rem,temp=0,k=1,pcode=0,x=1,num=0,var=1;
	for(i=0;i<size;i++){
		temp=employee_ids[i];
		pcode=temp/100;

		if(pcode==project_code){
			working_employee[count]=employee_ids[i]%100;
			count++;
		}
	}
	for(i=0;i<count;i++)
	printf("%d\n",working_employee[i]);
	getchar();
	getchar();
}
59.Array Addition in Reverse

In an export company, the clothes are stored in boxes and are shipped in three different ships. Each box has a number on it. The boxes are stored in ships in specific pattern as below:
1. First box number in Ship1 + Last box number in Ship2 = first box number in Ship3.
2. Second box number in Ship1 + Second Last box number in Ship2 = Second box number in ship3.
Similarly all the boxes are numbered in ship3. Assuming the count of boxes in each ship is equal, find the box numbers in ship3.

Include a function named arrayAddition that accepts 3 arguments and its return type is void.  The first argument is the input array 1, the second argument is the input array 2 and the third argument is an int that corresponds to the size of the array.  The output is stored in an array variable named output1.

If the size of the array (the number of boxes) is negative or if any element in any of the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of utmost 2n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the first array(i.e box numbers in ship 1). The last 'n' integers correspond to the elements in the second array (i.e box numbers in ship 2). If any of the inputs are invalid, then terminate the program.

Output consists of n integers that correspond to the box numbers in ship 3.

Assume that the maximum size of the array is 20.

Sample Input 1 :
5
23
2
5
32
76
2
9
21
42
4

Sample Output 1 :
27
44
26
41
78

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int output1[20];
void arrayAddition(int[],int[],int);
int main(){
	int size=0,input1[20],input2[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	arrayAddition(input1,input2,size);

	return 0;
}
void arrayAddition(int ar1[],int ar2[],int size){
	int i=0,j=0,k=0;
	for(i=0,j=size-1;i<size&&j>=0;i++,j--){
		output1[i] = ar1[i]+ar2[j];
		printf("%d\n",output1[i]);
	}
	getchar();
	getchar();
}
60.adjecentDifference
Read the question carefully and follow the input and output format.

Given an input Integer array, find the difference in the adjacent elements and print the largest difference

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of largest adjacent difference.

Print "Invalid array size" when size of the array is a negative number and terminate the program
Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named adjecentDifference(int numbers[], int size) whose return type is an integer

Sample Input 1:
7
2
4
5
1
9
3
8
Sample Output 1:
8

Hint: The AdjecentElement Diff are :2,1,4,8,6,5 and Maximum diff is 8 which is obtained by 2-4 =2, 4-5=1,5- 1 =4, 1-9=8,9-3=6,3-8 =5

Sample Input 2:
5
1
7
3
-8
Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int output1[20];
int adjecentDifference(int numbers[], int size);
int main(){
	int size=0,input1[20],i=0,diff=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	diff = adjecentDifference(input1,size);
	printf("%d",diff);
	getchar();
	getchar();
	return 0;
}
int adjecentDifference(int numbers[], int size){
	int i=0,j=0,max=0,diff=0;
	for(i=0;i<size-1;i++){
		if(numbers[i]>numbers[i+1])
			diff=numbers[i]-numbers[i+1];
		else
			diff=numbers[i+1]-numbers[i];
		if(diff>max)
			max=diff;
	}
	return max;
}
61.Duplicate Elements

Tim is working as a data entry staff in a college. His manager wants him to delete the duplicate student id from the entry. Help Tim in writing a program to delete the duplicate elements.

Include a function named eliminateDuplicate that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The output array is stored in a global variable named output1 and the number of elements in the output array is stored in the global variable named output 2.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer array.
Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20.

Sample Input 1:
8
1
6
3
5
6
8
5
9

Sample Output 1:
1
6
3
5
8
9


Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-200

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
void eliminateDuplicate(int[],int);
int main(){
	int n=0,input[20]={0},i;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	}

	eliminateDuplicate(input,n);


	return 0;
}
void eliminateDuplicate(int in[],int size){
	int i,j,k=0;
	for(i=0;i<size;i++){
		for(j=i+1;j<size;){
			if(in[i]==in[j]){
				for(k=j;k<size;k++)
					in[k]=in[k+1];
				size--;
			}
			else
				j++;
		}
	}
	for(i=0;i<size;i++)
		printf("%d\n",in[i]);
	getchar();
	getchar();
}

62.Second Smallest

Write a program to find the second smallest of all divisors of the given number.

For example, the divisors of 21 are 1,3,7 and 21. The second smallest divisor is 3.

Include a function named secondSmallest that accepts an integer argument and returns an integer. The function returns the second smallest divisor or returns -1 if it is a negative number or if it is greater than 32767.

If the function returns -1, print Invalid Input.

Input and Output Format:
Input consists of a single integer.
Output consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
21

Sample Output 1:
3

Sample Input 2:
-241

Sample Output 2:
Invalid Input

Sample Input 3:
50000

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int secondSmallest(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = secondSmallest(number);
	if(result!=-1)
		printf("%d",result);
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int secondSmallest(int n){
	int i;
	for(i=2;i<=n;i++){
         if(n%i==0){
			 break;
         }
     }
	return i;
}
63.secondMaxMinDiff
Read the question carefully and follow the input and output format.

Given an input array, find the difference b/w second largest and second smallest element in the array.

Hint : There is no repetition of element in the array.

Input and Output Format:

First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the difference b/w second largest and second smallest..

1) Print Invalid array size when size of the array is negative and terminate the program.
2) Print Invalid input when there is any negative numbers available in the input array and terminate the program.

Include a function named secondMaxMinDiff(int[] array, int n) whose return type is an integer, which is the difference b/w second largest and second smallest.

Sample Input 1:
5
1
2
3
4
5

Sample Output 1:
2

Sample Input 2:
4
-3

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int secondMaxMinDiff(int[], int n);
int main(){
	int size=0,input1[20],i=0,diff=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	diff = secondMaxMinDiff(input1,size);
	printf("%d",diff);
	getchar();
	getchar();
	return 0;
}
int secondMaxMinDiff(int array[], int n){
	int i=0,j=0,diff=0,temp=0;
	for(i=0;i<n;i++){
		for(j=i+1;j<n;j++){
			if(array[i]<array[j]){
				temp = array[i];
				array[i]=array[j];
				array[j]=temp;
			}
		}
	}
	diff=array[1]-array[n-2];
	return diff;
}
64.newNumber
Read the question carefully and follow the input and output format.

Write a program to find the difference between consecutive digits in the given input integer and display it.

Input and Output Format:
Input consists of an integer and output the difference between the consecutive digits.

Print "Number too small" if the number is less than 0
Print "Number too large" if the number is greater than 32767

Include a function named newNumber(int number) that returns a integer

Sample Input 1:
1325
Sample Output 1:
213

Sample Input 2:
-13
Sample Output 2:
Number too small

#include<stdio.h>
#include<stdlib.h>
int newNumber(int number);
int main(){
	int num=0,new_num=0;
	scanf("%d",&num);
	if(num>32767)
		printf("Number too large");
	else if(num<0)
		printf("Number too small");
	else{
		new_num=newNumber(num);
		printf("%d",new_num);
	}
	getchar();
	getchar();
	return 0;
}
int newNumber(int number){
	int rem,i=1,rem1=0,diff=0,digit=0;
	while(number>10){
		rem=number%10;
		number=number/10;
		rem1=number%10;
		if(rem>rem1)
			diff=rem-rem1;
		else
			diff=rem1-rem;
		digit=digit+(diff*i);
		i=i*10;
	}
	return digit;
}


65.Digit Counting

In a game show everybody got one coupon with some code. They need to count the digits in the code and send SMS to the given number.

Write a program to find the number of digits in the given number.

Include a function named countDigits that accepts an integer argument and returns an integer that corresponds to the number of digits. If the input is a negative number, the function returns -1.

If the function returns -1, print Invalid Input.

Input and Output Format:
Input consists of a single integer.
Output consists of an integer that corresponds to the number of digits in the input.


Sample Input 1:
250

Sample Output 1:
3

Sample Input 2:
-2345

Sample Output 2:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int countDigits(int number);
int main(){
	int num=0,digits=0;
	scanf("%d",&num);
	digits = countDigits(num);
	if(digits==-1)
		printf("invalid input");
	else
		printf("%d",digits);
	getchar();
	getchar();
	return 0;
}
int countDigits(int number){
	int rem,count=0;
	if(number<0)
		count=-1;
	else
	{
	while(number!=0){
		count++;
		number=number/10;
	}
	}
	return count;
}

66.maxScoreCount

Read the question carefully and follow the input and output format.

Student1 and Student2 are of same class and have recieved their scores for different subjects. Given each subject scores of the Student1 & Student2, Find out in how many subjects student1 has scored more marks than student2.

Input and Output Format :
First line of input corresponds to the n, the number of subjects. The next n lines correspond to the scores of Student 1 and the next n lines correspond to the scores of student 2. Output is the number of subjects student1 scored more marks than student2.

Print "Invalid size" when size of the array is a negative number and terminate the program
Print "Invalid score"  when there is any negative score and terminate the program

Include a function named maxScoreCount(int size,int student1[],int student2[]) that returns an integer, the number of subjects student1 scored more marks than student2

Sample Input 1:
7
45
23
67
34
88
13
67
33
56
89
44
67
89
55

Sample Output 1:
3

Sample Input 2:
-3
Sample Output 2:
Invalid size

Sample Input 3:
2
30
-60
Sample Output 3:
Invalid score
#include<stdio.h>
#include<stdlib.h>
int maxScoreCount(int size,int student1[],int student2[]);
int main(){
	int size=0,input1[20],input2[20],i=0,count=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	count = maxScoreCount(size,input1,input2);
	printf("%d",count);
	getchar();
	getchar();
	return 0;
}
int maxScoreCount(int size,int student1[],int student2[]){
	int i=0,count=0;
	for(i=0;i<size;i++){
		if(student1[i]>student2[i])
			count++;
	}
	return count;
}
67.nextPrime
Read the question carefully and follow the input and output format.

Write a program to find out the Next Prime to the given number.

Hint: number is always less than 100.

Input and Output Format :

First line of input consists of n, the number. Output is a single integer that displays the next prime.

Print "Number too large" when the given input number is greater than 32767 .
Print "Number too small" when given input is a negative number.

Include a function named nextPrime(int num) whose return type is an integer, the next prime.

Sample Input 1:
9

Sample Output 1:
11

Sample Input 2:
98987

Sample Output 2:
Number too large

#include<stdio.h>
#include<stdlib.h>
int nextPrime(int num);
int main(){
	int number=0,result;
	scanf("%d",&number);
	if(number<0)
		printf("number too small");
	else if(number>32767)
		printf("number too large");
	else{
	result = nextPrime(number);
	printf("%d",result);
	}
	getchar();
	getchar();
	return 0;
}

int nextPrime(int num){
	int next=0,i,m,c=0;
	for(i=num+1;i<100;i++){
		c=0;
		for(m=1;m<=i;m++){
			if(i%m==0)
				c++;
		}
		if(c==2)
			next=i;
		if(next!=0)
			break;
	}
	return next;
}
68.Array Average

Write a program to find the average of the array.

Include a function named avgArray that accepts 2 arguments and returns a float. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns a float that corresponds to the average of the array.

If the size of the array is negative or if any element in the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of a floating point number that corresponds to the average. It is displayed correct to 2 decimal places.
Assume that the maximum size of the array is 20.

Sample Input 1:
7
1
9
8
4
6
4
5

Sample Output 1:
5.29

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
float avgArray(int numbers[], int size);
int main(){
	int size=0,input1[20],i=0;
	float avg=0.0f;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	avg = avgArray(input1,size);
	printf("%.2f",avg);
	getchar();
	getchar();
	return 0;
}
float avgArray(int numbers[], int size){
	int i=0,j=0,max=0,sum=0;
	float avg=0.0f;
	for(i=0;i<size;i++){
		sum=sum+numbers[i];
	}
	avg=(float)sum/size;
	return avg;
}
69.Strong Number

Write a program to find whether the given input number is a Strong Number

Strong Number : (In a number sum of Factorial of individual digits equals to the same number).

Include a function named checkStrong that accepts an integer and returns an integer. The function returns
1.	1 if the input is a Strong Number
2.	0 if the input is not a Strong Number
3.	-1 if the input is a negative number

Print Invalid Input if the function returns -1.

Input and Output Format:
Input consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
145

Sample Output 1:
yes

Sample Input 2:
141

Sample Output 2:
no

Sample Input 3:
-2345

Sample Output 3:
Invalid Input

/*
num1=num;
 while(num){
  i=1,f=1;
  r=num%10;

  while(i<=r){
   f=f*i;
   i++;
  }
  sum=sum+f;
  num=num/10;

 }
 if(sum==num1)
  printf("%d is a strong number",num1);
 else
  printf("%d is not a strong number",num1);

*/

#include<stdio.h>
#include<stdlib.h>
int checkStrong(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = checkStrong(number);
	if(result==1)
		printf("yes");
	else if(result==0)
		printf("no");
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int checkStrong(int num){
	int res=0,f=0,r=0,num1=0,i,sum=0;
	if(num<0)
		res=-1;
	else{
		num1=num;
		while(num){
			i=1,f=1;
			r=num%10;
			while(i<=r){
				f=f*i;
				i++;
			}
			sum=sum+f;
			num=num/10;
		}
		if(sum==num1)
			res=1;
		else
			res=0;
	}
	return res;
}
70.Sum of Even Digits

In the computer science department, HOD wants to divide students into two groups based on their roll numbers. He decided to find the sum of the even digits in the roll number of each student and decided to split them into 2 groups based on this. Write a program to find the sum of the even digits in a number.

Include a function named addEvenDigits to find the sum of even digits in a number. This function accepts an integer argument and returns an integer. The function returns -1 if the roll number is less than zero or if the roll number is greater than 32767. Refer function specifications given at the end of the problem for further details.

If the roll number is less than 0 or if it exceeds 32767, print “Invalid Input”.

Input and Output Format:
The input consists of an integer that corresponds to the roll number.
The output consists of an integer that corresponds to the sum of the even digits in the roll number.

Sample Input 1:
3487

Sample Ouput 1:
12

Sample Input 2:
-8

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int addEvenDigits(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = addEvenDigits(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int addEvenDigits(int n){
	int res=0,i,rem=0;
	if(n<0 || n>32767)
		res = -1;
	else{
		while(n!=0){
			rem=n%10;
			if(rem%2==0)
				res=res+rem;
			n=n/10;
		}
	}
	return res;
}
61.Duplicate Elements

Tim is working as a data entry staff in a college. His manager wants him to delete the duplicate student id from the entry. Help Tim in writing a program to delete the duplicate elements.

Include a function named eliminateDuplicate that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The output array is stored in a global variable named output1 and the number of elements in the output array is stored in the global variable named output 2.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer array.
Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20.

Sample Input 1:
8
1
6
3
5
6
8
5
9

Sample Output 1:
1
6
3
5
8
9


Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-200

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
void eliminateDuplicate(int[],int);
int main(){
	int n=0,input[20]={0},i;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	}

	eliminateDuplicate(input,n);


	return 0;
}
void eliminateDuplicate(int in[],int size){
	int i,j,k=0;
	for(i=0;i<size;i++){
		for(j=i+1;j<size;){
			if(in[i]==in[j]){
				for(k=j;k<size;k++)
					in[k]=in[k+1];
				size--;
			}
			else
				j++;
		}
	}
	for(i=0;i<size;i++)
		printf("%d\n",in[i]);
	getchar();
	getchar();
}

62.Second Smallest

Write a program to find the second smallest of all divisors of the given number.

For example, the divisors of 21 are 1,3,7 and 21. The second smallest divisor is 3.

Include a function named secondSmallest that accepts an integer argument and returns an integer. The function returns the second smallest divisor or returns -1 if it is a negative number or if it is greater than 32767.

If the function returns -1, print Invalid Input.

Input and Output Format:
Input consists of a single integer.
Output consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
21

Sample Output 1:
3

Sample Input 2:
-241

Sample Output 2:
Invalid Input

Sample Input 3:
50000

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int secondSmallest(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = secondSmallest(number);
	if(result!=-1)
		printf("%d",result);
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int secondSmallest(int n){
	int i;
	for(i=2;i<=n;i++){
         if(n%i==0){
			 break;
         }
     }
	return i;
}
63.secondMaxMinDiff
Read the question carefully and follow the input and output format.

Given an input array, find the difference b/w second largest and second smallest element in the array.

Hint : There is no repetition of element in the array.

Input and Output Format:

First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the difference b/w second largest and second smallest..

1) Print Invalid array size when size of the array is negative and terminate the program.
2) Print Invalid input when there is any negative numbers available in the input array and terminate the program.

Include a function named secondMaxMinDiff(int[] array, int n) whose return type is an integer, which is the difference b/w second largest and second smallest.

Sample Input 1:
5
1
2
3
4
5

Sample Output 1:
2

Sample Input 2:
4
-3

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int secondMaxMinDiff(int[], int n);
int main(){
	int size=0,input1[20],i=0,diff=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	diff = secondMaxMinDiff(input1,size);
	printf("%d",diff);
	getchar();
	getchar();
	return 0;
}
int secondMaxMinDiff(int array[], int n){
	int i=0,j=0,diff=0,temp=0;
	for(i=0;i<n;i++){
		for(j=i+1;j<n;j++){
			if(array[i]<array[j]){
				temp = array[i];
				array[i]=array[j];
				array[j]=temp;
			}
		}
	}
	diff=array[1]-array[n-2];
	return diff;
}
64.newNumber
Read the question carefully and follow the input and output format.

Write a program to find the difference between consecutive digits in the given input integer and display it.

Input and Output Format:
Input consists of an integer and output the difference between the consecutive digits.

Print "Number too small" if the number is less than 0
Print "Number too large" if the number is greater than 32767

Include a function named newNumber(int number) that returns a integer

Sample Input 1:
1325
Sample Output 1:
213

Sample Input 2:
-13
Sample Output 2:
Number too small

#include<stdio.h>
#include<stdlib.h>
int newNumber(int number);
int main(){
	int num=0,new_num=0;
	scanf("%d",&num);
	if(num>32767)
		printf("Number too large");
	else if(num<0)
		printf("Number too small");
	else{
		new_num=newNumber(num);
		printf("%d",new_num);
	}
	getchar();
	getchar();
	return 0;
}
int newNumber(int number){
	int rem,i=1,rem1=0,diff=0,digit=0;
	while(number>10){
		rem=number%10;
		number=number/10;
		rem1=number%10;
		if(rem>rem1)
			diff=rem-rem1;
		else
			diff=rem1-rem;
		digit=digit+(diff*i);
		i=i*10;
	}
	return digit;
}


65.Digit Counting

In a game show everybody got one coupon with some code. They need to count the digits in the code and send SMS to the given number.

Write a program to find the number of digits in the given number.

Include a function named countDigits that accepts an integer argument and returns an integer that corresponds to the number of digits. If the input is a negative number, the function returns -1.

If the function returns -1, print Invalid Input.

Input and Output Format:
Input consists of a single integer.
Output consists of an integer that corresponds to the number of digits in the input.


Sample Input 1:
250

Sample Output 1:
3

Sample Input 2:
-2345

Sample Output 2:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int countDigits(int number);
int main(){
	int num=0,digits=0;
	scanf("%d",&num);
	digits = countDigits(num);
	if(digits==-1)
		printf("invalid input");
	else
		printf("%d",digits);
	getchar();
	getchar();
	return 0;
}
int countDigits(int number){
	int rem,count=0;
	if(number<0)
		count=-1;
	else
	{
	while(number!=0){
		count++;
		number=number/10;
	}
	}
	return count;
}

66.maxScoreCount

Read the question carefully and follow the input and output format.

Student1 and Student2 are of same class and have recieved their scores for different subjects. Given each subject scores of the Student1 & Student2, Find out in how many subjects student1 has scored more marks than student2.

Input and Output Format :
First line of input corresponds to the n, the number of subjects. The next n lines correspond to the scores of Student 1 and the next n lines correspond to the scores of student 2. Output is the number of subjects student1 scored more marks than student2.

Print "Invalid size" when size of the array is a negative number and terminate the program
Print "Invalid score"  when there is any negative score and terminate the program

Include a function named maxScoreCount(int size,int student1[],int student2[]) that returns an integer, the number of subjects student1 scored more marks than student2

Sample Input 1:
7
45
23
67
34
88
13
67
33
56
89
44
67
89
55

Sample Output 1:
3

Sample Input 2:
-3
Sample Output 2:
Invalid size

Sample Input 3:
2
30
-60
Sample Output 3:
Invalid score
#include<stdio.h>
#include<stdlib.h>
int maxScoreCount(int size,int student1[],int student2[]);
int main(){
	int size=0,input1[20],input2[20],i=0,count=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	count = maxScoreCount(size,input1,input2);
	printf("%d",count);
	getchar();
	getchar();
	return 0;
}
int maxScoreCount(int size,int student1[],int student2[]){
	int i=0,count=0;
	for(i=0;i<size;i++){
		if(student1[i]>student2[i])
			count++;
	}
	return count;
}
67.nextPrime
Read the question carefully and follow the input and output format.

Write a program to find out the Next Prime to the given number.

Hint: number is always less than 100.

Input and Output Format :

First line of input consists of n, the number. Output is a single integer that displays the next prime.

Print "Number too large" when the given input number is greater than 32767 .
Print "Number too small" when given input is a negative number.

Include a function named nextPrime(int num) whose return type is an integer, the next prime.

Sample Input 1:
9

Sample Output 1:
11

Sample Input 2:
98987

Sample Output 2:
Number too large

#include<stdio.h>
#include<stdlib.h>
int nextPrime(int num);
int main(){
	int number=0,result;
	scanf("%d",&number);
	if(number<0)
		printf("number too small");
	else if(number>32767)
		printf("number too large");
	else{
	result = nextPrime(number);
	printf("%d",result);
	}
	getchar();
	getchar();
	return 0;
}

int nextPrime(int num){
	int next=0,i,m,c=0;
	for(i=num+1;i<100;i++){
		c=0;
		for(m=1;m<=i;m++){
			if(i%m==0)
				c++;
		}
		if(c==2)
			next=i;
		if(next!=0)
			break;
	}
	return next;
}
68.Array Average

Write a program to find the average of the array.

Include a function named avgArray that accepts 2 arguments and returns a float. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns a float that corresponds to the average of the array.

If the size of the array is negative or if any element in the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of a floating point number that corresponds to the average. It is displayed correct to 2 decimal places.
Assume that the maximum size of the array is 20.

Sample Input 1:
7
1
9
8
4
6
4
5

Sample Output 1:
5.29

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
float avgArray(int numbers[], int size);
int main(){
	int size=0,input1[20],i=0;
	float avg=0.0f;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	avg = avgArray(input1,size);
	printf("%.2f",avg);
	getchar();
	getchar();
	return 0;
}
float avgArray(int numbers[], int size){
	int i=0,j=0,max=0,sum=0;
	float avg=0.0f;
	for(i=0;i<size;i++){
		sum=sum+numbers[i];
	}
	avg=(float)sum/size;
	return avg;
}
69.Strong Number

Write a program to find whether the given input number is a Strong Number

Strong Number : (In a number sum of Factorial of individual digits equals to the same number).

Include a function named checkStrong that accepts an integer and returns an integer. The function returns
1.	1 if the input is a Strong Number
2.	0 if the input is not a Strong Number
3.	-1 if the input is a negative number

Print Invalid Input if the function returns -1.

Input and Output Format:
Input consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
145

Sample Output 1:
yes

Sample Input 2:
141

Sample Output 2:
no

Sample Input 3:
-2345

Sample Output 3:
Invalid Input

/*
num1=num;
 while(num){
  i=1,f=1;
  r=num%10;

  while(i<=r){
   f=f*i;
   i++;
  }
  sum=sum+f;
  num=num/10;

 }
 if(sum==num1)
  printf("%d is a strong number",num1);
 else
  printf("%d is not a strong number",num1);

*/

#include<stdio.h>
#include<stdlib.h>
int checkStrong(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = checkStrong(number);
	if(result==1)
		printf("yes");
	else if(result==0)
		printf("no");
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int checkStrong(int num){
	int res=0,f=0,r=0,num1=0,i,sum=0;
	if(num<0)
		res=-1;
	else{
		num1=num;
		while(num){
			i=1,f=1;
			r=num%10;
			while(i<=r){
				f=f*i;
				i++;
			}
			sum=sum+f;
			num=num/10;
		}
		if(sum==num1)
			res=1;
		else
			res=0;
	}
	return res;
}
70.Sum of Even Digits

In the computer science department, HOD wants to divide students into two groups based on their roll numbers. He decided to find the sum of the even digits in the roll number of each student and decided to split them into 2 groups based on this. Write a program to find the sum of the even digits in a number.

Include a function named addEvenDigits to find the sum of even digits in a number. This function accepts an integer argument and returns an integer. The function returns -1 if the roll number is less than zero or if the roll number is greater than 32767. Refer function specifications given at the end of the problem for further details.

If the roll number is less than 0 or if it exceeds 32767, print “Invalid Input”.

Input and Output Format:
The input consists of an integer that corresponds to the roll number.
The output consists of an integer that corresponds to the sum of the even digits in the roll number.

Sample Input 1:
3487

Sample Ouput 1:
12

Sample Input 2:
-8

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int addEvenDigits(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = addEvenDigits(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int addEvenDigits(int n){
	int res=0,i,rem=0;
	if(n<0 || n>32767)
		res = -1;
	else{
		while(n!=0){
			rem=n%10;
			if(rem%2==0)
				res=res+rem;
			n=n/10;
		}
	}
	return res;
}
	71.commonElementsSum
Read the question carefully and follow the input and output format.

Given 2 integer arrays , write a program to find the sum of common elements in both the arrays.

If there are no common elements print 0.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the first array elements and the next n lines correspond to the second array elements. Output consist of an integer, which is the sum

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named commonElementsSum(int elements1[],int elements2[],int size) whose return type is an integer, the sum.

Sample Input 1:
4
1
2
3
4
2
3
6
7

Sample Output 1:
5

Sample Input 2:
3
8
6
-7

Sample Output 2:
Invalid input


#include<stdio.h>
#include<stdlib.h>
int common[20];
int commonElementsSum(int elements1[],int elements2[],int size);
int main(){
	int size=0,input1[20],input2[20],i=0,sum=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	sum=commonElementsSum(input1,input2,size);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int commonElementsSum(int elements1[],int elements2[],int size){
	int i=0,j=0,k=0,temp=0,sum=0;
	for(i=0;i<size;i++){
		for(j=0;j<size;j++){
			if(elements1[i]==elements2[j]){
				common[k]=elements1[i];
				k++;
			}
		}
	}
	for(i=0;i<k;i++)
		sum=sum+common[i];
	return sum;

}
72.Palindromic Number

Write a program to find whether the given input number is a palindrome.

Include a function named checkPalindrome that accepts an integer and returns an integer. The function returns
1.	1 if the input is a palindrome
2.	0 if the input is not a palindrome
3.	-1 if the input is a negative number

Print Invalid Input if the function returns -1.

Input and Output Format:
Input consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
2002

Sample Output 1:
yes

Sample Input 2:
167

Sample Output 2:
no

Sample Input 3:
-2345

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int checkPalindrome (int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = checkPalindrome (number);
	if(result==1)
		printf("yes");
	else if(result==0)
		printf("no");
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int checkPalindrome (int n){
	int res=0,temp=0,rem=0,sum=0,reverse=0;
	if(n<0)
		res=-1;
	else{
		 temp=n;
		 while(temp!=0){
			 rem=temp%10;
			 reverse=reverse*10+rem;
			 temp/=10;
		}
		 if(reverse==n)
			 res=1;
		 else
			 res=0;
	}
	return res;
}
73.sumEvenIndex
Read the question carefully and follow the input and output format.

Write a program to find the sum of the indexes (positions) of even numbers in the Array. Consider 0 index as 1 and 1 index is 2 and so on……
Note : Assume Array Index Starts From 1

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the sum.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named sumEvenIndex(int numbers[], int size) whose return type is an integer, which is the sum..
Sample Input 1:
7
4
2
7
9
1
10
13

Sample Output 1:
9

Sample Input 2:
-13

Sample Output 2:
Invalid array size
#include<stdio.h>
#include<stdlib.h>
int sumEvenIndex(int numbers[], int size);
int main(){
	int n=0,sum=0,input[30],i,flag=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=1;i<=n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	sum = sumEvenIndex(input,n);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int sumEvenIndex(int numbers[], int size){
	int i=0,sum=0;
	for(i=1;i<=size;i++){
		if(numbers[i]%2==0)
			sum=sum+i;
	}
	return sum;
}
74.sumEvenOddProduct
Read the question carefully and follow the input and output format.

Write a program to find the sum of  product of even digits  and product of odd digits in a given number.

If number contains only even numbers or odd numbers take the other numbers product as 1.

Input and Output Format :
Input consists of a single integer. Output consist of the sum of even digit product and odd digit product.

Print "Number too large" when the given input number is greater than 32767
Print "Number too small" when the given input number is a negative number.

Include a function named sumEvenOddProduct(int number) whose return type is integer, the sum

Sample Input 1:
4564
Sample Output 1:
101

{Hint :   (4*6*4) + (5)  =  96 +5 = 101}
Sample Input 2:
1357
Sample Output 2:
106


Sample Input 3:
981357
Sample Output 3:
Number too large

#include<stdio.h>
#include<stdlib.h>
int sumEvenOddProduct(int number);
int main(){
	int number,result=0;
	scanf("%d",&number);
	if(number>32767)
		printf("number too large");
	else if(number<0)
		printf("number too small");
	else
	{
		result = sumEvenOddProduct(number);
		printf("%d",result);
	}
	getchar();
	getchar();
	return 0;
}

int sumEvenOddProduct(int number){
	int res=0,i,rem=0,evenprod=1,oddprod=1;
		while(number!=0){
			rem=number%10;
			if(rem%2==0)
				evenprod=evenprod*rem;
			else
				oddprod=oddprod*rem;
			number=number/10;
		}
		res = evenprod + oddprod;
		return res;
}

75.Sum of the Digits

In a lucky draw everybody got one coupon with some code. They need to sum the digits in the code and send SMS to the given number. Write a program to find the sum of digits in a number.

Include a function named sumDigits that accepts an integer argument and returns an integer that corresponds to the sum of the digits. The function returns -1 if the input is less than zero or if the roll number is greater than 32767.

If the function returns -1, print “Invalid Input”.

Input and Output Format:

The input consists of an integer.
The output consists of an integer that corresponds to the sum of the digits in the number.

Sample Input 1:
3487

Sample Ouput 1:
22

Sample Input 2:
-8

Sample Output 2:
Invalid Input



#include<stdio.h>
#include<stdlib.h>
int sumDigits(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = sumDigits(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int sumDigits(int n){
	int res=0,i,rem=0;
	if(n<0 || n>32767)
		res = -1;
	else{
		while(n!=0){
			rem=n%10;
			res=res+rem;
			n=n/10;
		}
	}
	return res;
}
76.Sum of squares of prime numbers

Given an integer n, write a program to find the sum of squares of prime numbers upto and including n.

Include a function named sumSquarePrime that accepts an integer argument and returns an integer that corresponds to result. The function returns -1 if the input is less than zero or if the number is greater than 32767.

If the function returns -1, print “Invalid Input”.

Please note that 1 is neither prime nor composite.

Input and Output Format:

The input consists of an integer.
The output consists of an integer that corresponds to the sum of the squares of prime numbers.

Sample Input 1:
10

Sample Ouput 1:
87

Sample Input 2:
-8

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int sumSquarePrime(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = sumSquarePrime(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int sumSquarePrime(int n){
	int i,count=0,num,sum=0;
	for(num = 1;num<=n;num++){
		count=0;
		for(i=1;i<=num;i++){
			if(num%i==0)
			count++;
		}
		if(count==2)
			sum=sum+(num*num);

	}
	return sum;
}
77.3/5 Number

Write a program to find whether the given number is a 3/5 Number.

A number is a 3/5 Number if the product of the digits in the number is divisible by 3 or 5.

Include a function named divisibleByThreeFive that accepts an integer argument and returns an integer. The function returns
1.	1 if it is a 3/5 Number
2.	0 if it is not a 3/5 Number
3.	-1 if it is a negative number

Input and Output Format:
Input consists of a single integer.
Output consists of a string.
Refer sample output for formatting specifications.


Sample Input 1:
251

Sample Output 1:
yes

Sample Input 2:
241

Sample Output 2:
no

Sample Input 3:
-9

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int divisibleByThreeFive(int);
int main(){
	int number=0,result;
	scanf("%d",&number);
	result = divisibleByThreeFive(number);
	if(result==1)
		printf("yes");
	else if(result==0)
		printf("no");
	else
		printf("Invalid input");
	getchar();
	getchar();
	return 0;
}

int divisibleByThreeFive(int n){
	int res=1,i,rem=0,prod=1;
	if(n<0)
		res = -1;
	else{
		while(n!=0){
			rem=n%10;
			prod=prod*rem;
			n=n/10;
		}
		if(prod%3==0 || prod%5==0)
			res=1;
		else
			res=0;
	}
	return res;
}



78.aboveAverageMarks
Read the question carefully and follow the input and output format.

Given an input array that represents the marks of students, find out the marks which are greater than or equal to average mark of all students.

Input and Output Format:
First line of input consists of n, the number of elements in the input array.
Next n lines correspond to the array elements. Output consist of an integer array.

1) Print "Invalid array size" when size of the array is negative and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named aboveAverageMarks(int array[], int size) whose return type is void.
The output array is stored in a global variable named above_average.

Sample Input 1:
5
10
20
30
40
50
Sample Output 1:
30
40
50

Sample Input 2:
4
-3
Sample Output 2:
Invalid Input
#include<stdio.h>
#include<stdlib.h>
void aboveAverageMarks(int array[], int size);
int main(){
	int size=0,input1[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	aboveAverageMarks(input1,size);
	return 0;
}
void aboveAverageMarks(int array[], int size){
	int i=0,j=0,avg=0,sum=0;
	for(i=0;i<size;i++)
		sum=sum+array[i];
	avg=sum/size;
	for(i=0;i<size;i++){
		if(array[i]>=avg)
			printf("%d\n",array[i]);
	}
	getchar();
	getchar();
}
79.changeNumber
Read the question carefully and follow the input and output format.

Tom needs to generate a new number from the given input with the following conditions.Consider Input is always a 3 digit number.

conditions:
(i) Middle digit comes first.
(ii) Last digit should come in middle
(iii) First digit should come as a last digit


Business rule:
1. Print "Invalid input" if input is negative number.
2. Print "Not a 3 digit number" if the given number is not a 3 digit number.
158
581
Include a function named changeNumber(int number) that returns an integer.

Input and Output Format:
Input consists of an integer.
Refer business rules and sample output for output format.

Sample Input 1:
123
Sample Output 1:
231


Sample Input 2:
1234
Sample Output 2:
Not a 3 digit number
#include<stdio.h>
#include<stdlib.h>
int changeNumber(int n);
int main(){
	int number=0,result;
	scanf("%d",&number);
	if(number<0)
		printf("invalid input");
	else if(number<100 || number>999)
		printf("Not a three digit number");
	else{
		result = changeNumber(number);
		printf("%d",result);
	}
	getchar();
	getchar();
	return 0;
}

int changeNumber(int n){
	int rem=0,d1,d2,d3,i=1,temp=1,res=0;
	do{
		rem=n%10;
		d3=rem;
		n=n/10;
		rem=n%10;
		d2=rem;
		n=n/10;
		rem=n%10;
		d1=rem;
	}while(0);
	do{
		res=res+(d1*i);
		i=i*10;
		res=res+(d3*i);
		i=i*10;
		res=res+(d2*i);
	}while(0);
	return res;
}
80.differentElements
Read the question carefully and follow the input and output format.

Given two input arrays find out the elements which are not common.

Input and Output Format:

First line of input consists of n, the number of elements. Next n lines correspond to the first array elements and the next n lines correspond to the second array elements. Output consist of an integer array, which contains the elements that are not common between the first and second array.

1) Print Invalid array size when size of the array is a negative number and terminate the program.
2) Print Invalid input when there is any negative numbers available in the input array and terminate the program.

Include a function named differentElements(int set1[], int set2[], int size) whose return type is void.
The output array is stored in a global variable named not_common.

Sample Input 1:
5
1 2 3 4 5
5 6 4 8 7

Sample Output 1:
1
2
3
6
8
7

Sample Input 2:
5
1 4 8 9 4
-8
Sample Output 2:
Invalid input

#include<stdio.h>
#include<stdlib.h>
int not_common[20];
void differentElements(int set1[], int set2[], int size);
int main(){
	int size=0,input1[20],input2[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid Array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	differentElements(input1,input2,size);

	return 0;
}
void differentElements(int set1[], int set2[], int size){
	int i=0,j=0,k=0,flag=0,flag1=0;
	for(i=0;i<size;i++){
		flag=0;
		for(j=0;j<size;j++){
			if(set1[i]==set2[j])
				flag=1;
		}
		if(flag==0){
		not_common[k]=set1[i];
		k++;
		}
	}
	for(i=0;i<size;i++){
		flag1=0;
		for(j=0;j<size;j++){
			if(set2[i]==set1[j])
				flag1=1;
		}
		if(flag1==0){
		not_common[k]=set2[i];
		k++;
		}
	}
	for(i=0;i<k;i++)
		printf("%d\n",not_common[i]);
	getchar();
	getchar();
}

81.registerAccountNumbers

Read the question carefully and follow the input and output format.

Given an array in which the elements are in xxxyy format, where first xxx digits represent the Branch code and the yy represents the account
id.  Find out the No of accounts in the given branch code

Input and Output Format :
The first input n corresponds to the size of the array, the next n lines correspond to the elements of the array and the last line of the input corresponds to the branch code.
Output corresponds to the number of accounts in the given branch code
If the given branch code is not available, print 0.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program
2) Print "Invalid account Number" when there is any negative number available in the input array and terminate the program
3) Print "Invalid branch code" when branch code is negative number and terminate the program

Include a function named registerAccountNumbers (int size, int account_numbers[], int branch_code) that returns the no of accounts

Sample Input 1 :
6
12345
12370
12324
13355
13333
14575
123

Sample Output 1 :
3

Sample Input 2 :
-6

Sample Output 2:
Invalid array size

#include<stdio.h>
#include<stdlib.h>
int registerAccountNumbers (int size, int account_numbers[], int branch_code);
int main(){
	int n=0,no_of_acc=0,input[30],i,flag=0,bcode=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid account number");
		getchar();
		getchar();
		exit(0);
	}
	scanf("%d",&bcode);
	if(bcode<0){
		printf("Invalid branch code");
		getchar();
		getchar();
		exit(0);
	}
	no_of_acc=registerAccountNumbers(n,input,bcode);
	printf("%d",no_of_acc);
	getchar();
	getchar();
	return 0;
}
int registerAccountNumbers(int size, int account_numbers[], int branch_code){
	int count=0,i,rem,temp=0,k=1,bcode=0,x=1;
	for(i=0;i<size;i++){
		temp=account_numbers[i];
		bcode=temp/100;
		if(bcode==branch_code)
			count++;
	}
	return count;
}
82.clearedStage1
Read the question carefully and follow the input and output format.

Given an integer array. The first index represents the Student id, Second index represents C-programming marks and the third index Represents SQL marks. Write a program to find the Ids of students who have cleared both C-programming and SQL.

Note :(1) The Pass Marks is >=70

Input and Output Format :

First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer array.

1) Print "Invalid array size" when size of the array is negative and terminate the program.
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named clearedStage1(int array[], int size) whose return type is void.
The output array is stored in a global variable named cleared.

Sample Input 1:
9
1
25
75
3
75
80
2
75
75

Sample Output 1:
3
2

Sample Input 2:
6
4
25
-78

Sample Output 2:
Invalid input

#include<stdio.h>
#include<stdlib.h>
int registerAccountNumbers (int size, int account_numbers[], int branch_code);
int main(){
	int n=0,no_of_acc=0,input[30],i,flag=0,bcode=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0)
			flag=1;
	}
	if(flag==1){
		printf("Invalid account number");
		getchar();
		getchar();
		exit(0);
	}
	scanf("%d",&bcode);
	if(bcode<0){
		printf("Invalid branch code");
		getchar();
		getchar();
		exit(0);
	}
	no_of_acc=registerAccountNumbers(n,input,bcode);
	printf("%d",no_of_acc);
	getchar();
	getchar();
	return 0;
}
int registerAccountNumbers(int size, int account_numbers[], int branch_code){
	int count=0,i,rem,temp=0,k=1,bcode=0,x=1;
	for(i=0;i<size;i++){
		temp=account_numbers[i];
		bcode=temp/100;
		if(bcode==branch_code)
			count++;
	}
	return count;
}
83.findLargest
Read the question carefully and follow the input and output format.

Write a program to find the largest of the 3 given numbers.

Input and Output Format :
Input consists of 3 integers. Output consist of an integer that is the maximum.

Print "Number too large" when any of given input numbers is greater than 32767 .
Print "Number too small" when given input is a negative number.

Include a function named findLargest(int num1, int num2, int num3) whose return type is an integer, which is the largest.

Sample Input 1:
2
3
4

Sample Output 1:
4

Sample Input 2:
98974

Sample Output 2:
Number too large

Sample Input 3:
-32767

Sample Output 3:
Number too small
84.sumThreeLargest
Read the question carefully and follow the input and output format.

Write a program to find the sum of first ,second and third largest element in the given array.

Input and Output Format:
First line of input consists of n, the number of elements. Next n lines correspond to the array elements . Output consists of an Integer, the sum.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named sumThreeLargest(int array[], int n) whose return type is integer

Sample Input 1:
8
1
2
2
3
4
5
5
4

Sample Output 1:
12

Sample Input 2:
4
1
2
-3
Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int sumThreeLargest(int array[], int n);
int main(){
	int n=0,input[20]={0},i,largest;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	}

	largest = sumThreeLargest(input,n);
	printf("%d",largest);
	getchar();
	getchar();
	return 0;
}
int sumThreeLargest(int array[], int n){
	int i,j,k=0,temp=0;
	for(i=0;i<n;i++){
		for(j=i+1;j<n;){
			if(array[i]==array[j]){
				for(k=j;k<n;k++)
					array[k]=array[k+1];
				n--;
			}
			else
				j++;
		}
	}
	for(i=0;i<n;i++){
		for(j=i+1;j<n;j++){
			temp = array[i];
			array[i] = array[j];
			array[j] = temp;
		}
	}
	return array[0]+array[1]+array[2];
}
85.highestProfitYear
Read the question carefully and follow the input and output format.

An array holds information of a company profit margin and year. Find out the year in which highest revenue was earned. Assume the first index of array indicates year and the next index indicates the amount of money earned by the company and so on.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the sum

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative number available in the input array and terminate the program.

Include a function named highestProfitYear(int revenue[],int size) whose return type is an integer, which is the year.

Sample Input 1:
6
2012
10000
2011
5000
2009
4000

Sample Output 1:
2012

Sample Input 2:
8
2015
89745
-2015

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int highestProfitYear(int revenue[],int size);
int main(){
	int n=0,input[20]={0},i,highest;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	}

	highest = highestProfitYear(input,n);
	printf("%d",highest);
	getchar();
	getchar();
	return 0;
}
int highestProfitYear(int revenue[],int size){
	int i,j,k=0,highest=0,max=0;
	for(i=1;i<size;i=i+2){
		if(revenue[i]>max){
			max=revenue[i];
			highest=revenue[i-1];
		}
	}

	return highest;
}

86.countNoOfConnections
Read the question carefully and follow the input and output format.

Given an input array, the elements are of format XYYY . where X represents the connection type. YYY represents the connection id.

If X is 2 -> means 2G connection
If X is 3 -> means 3G connection
If X is 4 -> means 4G connection
You need to find the number of type of connections.

Note:
If a particular connection type (starting with 2 or 3 or 4) is not available represent with zero in the corresponding position.

Include a function named countNoOfConnections(int connection_list[],int no) that returns the number of types of connections

Business Rules :
1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid connection" when there is any negative number available in the input array and terminate the program

Input and Output Format :
First line of input corresponds to n, next n lines corresponds to the elements of the array
Output consists of the the number of type of connections. [1st line of the output corresponds to the number of 2G connections, 2nd line corresponds to the number of 3G connections and 3rd line corresponds to the number of 4G connections]

Sample Input 1 :
5
2333
3101
2102
4567
3123

Sample Output 1:
2
2
1

Sample Input 2 :
2
-2234


Sample Output 2:
Invalid connection

#include<stdio.h>
#include<stdlib.h>
void countNoOfConnections(int connection_list[],int no);
int main(){
	int n=0,input[20]={0},i;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0){
		printf("Invalid Connection");
		getchar();
		getchar();
		exit(0);
	}
	}

	countNoOfConnections(input,n);

	getchar();
	getchar();
	return 0;
}
void countNoOfConnections(int connection_list[],int no){
	int i,j,k=0,temp=0,x=0,two=0,three=0,four=0,other=1,out[10]={0};
	for(i=0;i<no;i++){
		temp=connection_list[i];
		x=temp/1000;

		if(x==2)
			two++;
		else if(x==3)
			three++;
		else if(x==4)
			four++;
		else
			other=0;
	}
	out[0]=two;
	out[1]=three;
	out[2]=four;

	for(i=0;i<3;i++)
		printf("%d\n",out[i]);
}
87.Sum of positive numbers in Array

Write a program to find the sum of positive numbers in an array.

Include a function named addPositives that accepts 2 arguments and returns an int. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns the sum of the positive numbers in the array.

If the size of the array is negative, print “Invalid Input” and terminate the program..

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Assume that the maximum size of the array is 20.

Sample Input 1:
5
3
5
-2
6
-6


Sample Output 1:
14

Sample Input 2:
-5

Sample Output 2:
Invalid Input
#include<stdio.h>
#include<stdlib.h>
int addPositives(int array[],int n);
int main(){
	int n=0,input[20]={0},i,sum;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++)
		scanf("%d",&input[i]);



	sum=addPositives(input,n);
	printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int addPositives(int array[],int n){
	int i,j,sum=0;
	for(i=0;i<n;i++){
		if(array[i]>0)
			sum=sum+array[i];
	}
	return sum;

}
88.Find Index

Write a program to find the index of a particular number in a given input array.

Include a function named findIndex that accepts 3 arguments and returns an int. The first argument is the input array, the second argument is an int that corresponds to the size of the array and the third argument is the element to be searched for. The function returns the corresponding index if the search element is present in the array and returns -1 if the search element is not present in the array.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.


Input and Output Format:
Input consists of n+2 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array. The last integer corresponds to the element whose count needs to be found.
Output consists of an integer that corresponds to the index of the search element if it is present.
Else, print 'not found'.

Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20 and that all elements in the array are unique.

Sample Input 1:
8
2
1
3
8
6
12
10
19
8

Sample Output 1:
3

Sample Input 2:
8
2
1
3
8
6
12
10
19
80

Sample Output 2:
not found

Sample Input 3:
-5

Sample Output 3:
Invalid Input

Sample Input 4:
5
23
2
-200

Sample Output 4:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int cricketer[20];
int findIndex(int,int[],int);
int main(){
	int n=0,index=0,input[30],i,search_element=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
		scanf("%d",&input[i]);
		if(input[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
	}
	}
		scanf("%d",&search_element);
		index = findIndex(n,input,search_element);
			if(index==-1)
				printf("not found");
			else
				printf("%d",index);
		getchar();
		getchar();
		return 0;
}
	int findIndex( int size,int array[], int search){
	int index,i,f=0;
	for(i=1 ; i<size ; i=i+2)
	{
		if(array[i]==search){
			f=1;
			index = array[i-1];
			break;
		}
	}
	if(f==1)
		return index;
	else
		return -1;
}
89.Store Consequtives

Write a program to obtain a new array that contains the consequtive values of the given input array. The output array is named as output1.

Include a function named storeConsequtives that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array .  The output array is stored in a global variable named output1.

If the size of the array is negative or if any of the elements in the array are negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer array.
Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20.

Sample Input 1:
4
2
5
1
4

Sample Output 1:
3
6
2
5

Sample Input 2:
-5

Sample Output 2:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int output1[20];
void storeConsequtives(int numbers[], int size);
int main(){
	int size=0,input1[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	storeConsequtives(input1,size);
	return 0;
}
void storeConsequtives(int numbers[], int size){
	int i=0,j=0;
	for(i=0;i<size;i++){
		output1[i]=numbers[i]+1;
		printf("%d\n",output1[i]);
	}
	getchar();
	getchar();
}
90.findGrade
Read the question carefully and follow the input and output format.

In a school examination the result of students are published in the form of an array where first index is the student id and the second index is the total marks in mathematics third index is student id and fourth index is total marks in mathematics and so on... Write a method that assigns the student id as the key and the grade in mathematics as the value to the output array based on the following conditions:

If(Marks >=90 ) : 1
If(Marks >=80 and <90 ) : 2
If(Marks >=70 and <80) : 3
If(Marks <70 ) : 0

Hint: Array size is always is even.

Input and Output Format :

First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer array.
1) Print "Invalid array size" when size of the array is negative and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named findGrade(int array[], int size) whose return type is void.
The output array is stored in a global variable named grade.

Sample Input 1:
10
1
65
2
74
3
86
4
95
6
69
Sample Output 1:
1
0
2
3
3
2
4
1
6
0

Sample Input 2:
4
-3
Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int grade[20];
void findGrade(int array[], int size);
int main(){
	int size=0,input1[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	findGrade(input1,size);
	return 0;
}
void findGrade(int array[], int size){
	int i=0,j=0;
	for(i=1;i<size;i=i+2){
		if(array[i]>=90){
			grade[i-1]=array[i-1];
			grade[i]=1;
		}
		else if(array[i]>=80 && array[i]<90){
			grade[i-1]=array[i-1];
			grade[i]=2;
		}
		else if(array[i]>=70 && array[i]<80){
			grade[i-1]=array[i-1];
			grade[i]=3;
		}
		else{
			grade[i-1]=array[i-1];
			grade[i]=0;
		}
	}
	for(i=0;i<size;i++)
		printf("%d\n",grade[i]);
	getchar();
	getchar();
}
91.Odd Even Average

The Owner of a block visited the Layout and found that he has some plot numbers of his own and some are odd numbers and some are even numbers. He is maintaining the details in a file in the system. For the password protection our owner has followed one formula. He calculated the sum of his even numbers plot and sum of odd numbers plot and found the average of those two and he used that average as his password for the details file. Find the password that our owner has arrived.

Include a function named avgOddEvenSum that accepts 2 arguments and returns a float. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns a float that corresponds to the average of the array.

If the size of the array is negative or if any element in the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of a floating point number that corresponds to the average. It is displayed correct to 2 decimal places.
Assume that the maximum size of the array is 20.

Sample Input 1:
5
1
2
3
4
5

Sample Output 1:
7.50

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
float avgOddEvenSum(int[],int);
int main(){
	int n=0,i,flag=0,input[20];
	float avg=0.0f;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0)
		flag=1;
	}
	if(flag==1){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	avg = avgOddEvenSum(input,n);
	printf("%0.2f",avg);
	getchar();
	getchar();
	return 0;
}
float avgOddEvenSum(int array[],int size){
	float avg;
	int i,sumodd=0,sumeven=0;
	for(i=0;i<size;i++){
		if(array[i]%2==0)
			sumeven=sumeven+array[i];
		else
			sumodd=sumodd+array[i];
	}
	avg = float(sumeven+sumodd)/2.0f;
	return avg;
}
92.convertToBinary
Read the question carefully and follow the input and output format.

Kate is a military officer. He needs to send top-secret code to the other soldiers in a different place. He need to encrypt it. We need to write a function to convert the given decimal number to the corresponding binary number.

Input consist of single integer. Output consists of binary number.

1) Print "Number too small" when input is negative.
2) Print "Number too large" when input value is greater than 100.

Include a function named convertToBinary(int num) whose return type is void.

Sample Input 1:
12

Sample Output 1:
1100

Sample Input 2:
101

Sample Output 2:
Number too large


#include<stdio.h>
#include<stdlib.h>
void convertToBinary(int num);
int main(){
	int number=0;
	scanf("%d",&number);
	if(number<0)
		printf("Number too small");
	else if(number>100)
		printf("Number too large");
	else
		convertToBinary(number);
	return 0;
}
void convertToBinary(int num){
	  int a[20],i=0;
      while(num>0)
      {
           a[i]=num%2;
           i++;
           num=num/2;
      }
      for(int j=i-1;j>=0;j--)
            printf("%d",a[j]);
	getchar();
	getchar();
}

93.reverseNumber
Read the question carefully and follow the input and output format.

Write a program to find  the reverse of a given input integer

Input and Output Format :
Input consists of an integer, n.  Output consist of the reverse of the number n.

Print "Number too large" when the given input number is greater than 32767
Print "Number too small" when the given input numbers is a negative number.

Include a function named reverseNumber(int num) whose return type is integer, the reverse of n.

Sample Input 1:
1234

Sample Output 1:
4321

Sample Input 2:
326357

Sample Output 2:
Number too large
#include<stdio.h>
#include<stdlib.h>
int reverseNumber(int num);
int main(){
	int number=0,revnumber=0;
	scanf("%d",&number);
	if(number<0)
		printf("Number too small");
	else if(number>32767)
		printf("Number too large");
	else{
		revnumber = reverseNumber(number);
		printf("%d",revnumber);
	}
	getchar();
	getchar();
	return 0;
}
int reverseNumber(int num){
	int reverse=0;
	     while (num != 0)
		 {
			 reverse = reverse * 10;
			 reverse = reverse + num%10;
			 num=num/10;
		}
		 return reverse;
}
94.Sum of Prime Cubes

Given an input integer n, write a program to find the sum of the cubes of the prime numbers upto n. (including n)

Please note that 1 is neither prime nor composite.

Include a function named sumCubeOfPrime that accepts an integer argument and returns an integer. The function returns -1 if the input is a negative number or if it is greater than 3000.

If the function returns -1, print Invalid Input.

Input and Output Format:
Input consists of a single integer.
Output consists of a single integer.
Refer sample output for formatting specifications.


Sample Input 1:
5

Sample Output 1:
160

Sample Input 2:
-241

Sample Output 2:
Invalid Input

Sample Input 3:
50000

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int sumCubeOfPrime(int);
int main(){
	int number,result=0;
	scanf("%d",&number);
	result = sumCubeOfPrime(number);
	if(result==-1)
		printf("Invalid input");
	else
		printf("%d",result);
	getchar();
	getchar();
	return 0;
}

int sumCubeOfPrime(int n){
	int i,count=0,num,sum=0;
	if(n<0 || n>3000)
		sum=-1;
	else{

	for(num = 1;num<=n;num++){
		count=0;
		for(i=1;i<=num;i++){
			if(num%i==0)
			count++;
		}
		if(count==2)
			sum=sum+(num*num*num);

	}
	}
	return sum;
}
95.Negative Elements

Write a program to remove all the negative elements of the input array , sort the positive elements and stores them in an output array .

Include a function named eliminateNegatives that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The output array is stored in a global variable named output1 and the size of the output array is stored in a global variable named output2.

If the size of the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer array.
Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20.

Sample Input 1:
8
1
6
3
5
-6
8
-15
9

Sample Output 1:
1
3
5

6
8
9


Sample Input 2:
-5

Sample Output 2:
Invalid Input
 #include<stdio.h>
#include<stdlib.h>
int output1[20];
void eliminateNegatives(int[],int);
int main(){
	int size=0,input1[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++)
		scanf("%d",&input1[i]);

	eliminateNegatives(input1,size);

	return 0;
}
void eliminateNegatives(int array[],int size){
	int i=0,k=0,j=0,temp=0;
	for(i=0;i<size;i++){
		if(array[i]>0){
			output1[k]=array[i];
			k++;
		}
	}
	for(i=0;i<k;i++){
		for(j=i+1;j<k;j++){
			if(output1[i]>output1[j]){
			temp = output1[i];
			output1[i]=output1[j];
			output1[j]=temp;
			}
		}
	}
	for(i=0;i<k;i++)
		printf("%d\n",output1[i]);
	getchar();
	getchar();
}


96.Savings Calculation
Jim got salary for this month and he spends 50% of his salary for food and 20% of his salary for travel. If the number of days he worked is 31 he gets a bonus of Rs.500. Write a program to find how much he can save in his pocket after spending all these?

Include a function named calculateSavings that accepts 2 integer arguments and returns a float. The first integer corresponds to Jim's basic salary and the second integer corresponds to the number of days Jim has worked. The function returns a float that corresponds to the amount that Jim could save.

Print Invalid Input and terminate the program in the following cases:
1.	Basic salary is greater than 9000
2.	Number of working days is greater than 31
3.	Basic salary is negative
4.	Number of working days is negative

Input and Output Format:
Input consists of 2 integers. The first integer corresponds to Jim's basic salary and the second integer corresponds to the number of days he has worked.
Output consists of a single float that corresponds to Jim's savings. Jim's savings is displayed correct to 2 decimal places.

Sample Input 1:
7000
30

Sample Output 1:
2100 .00


Sample Input 2:
50000


Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
float calculateSavings(int,int);
int main(){
	int basic=0,days=0;
	float save=0.0f;
	scanf("%d%d",&basic,&days);
	if(basic>9000 || days>31 || basic<0 || days<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	save = calculateSavings(basic,days);
	printf("%0.2f",save);
	getchar();
	getchar();
	return 0;
}

float calculateSavings(int basic,int days){
	float spent=0.0f,savings=0.0f;
	spent=(float)(basic*70)/100;
	if(days==31)
		savings = basic+500-spent;
	else
		savings = basic-spent;
	return savings;
}

97.studentMarks
Read the question carefully and follow the input and output format.

The Given input is of the format XXXYY , where XXX is Id , YY is marks. Write a code to display the id and marks separately as given in the output formats. [Refer sample input and output]

Input and Output Format :
Input consists of a number. Refer sample output for output format.

Print "Number too large" when any of given input numbers is greater than 32767 .
Print "Number too small" when given input is a negative number.

Include a function named studentMarks(int number) whose return type is void.

Sample Input 1:
12345

Sample Output 1:
123
45

Sample Input 2:
-13

Sample Output 2:
Invalid input

#include<stdio.h>
#include<stdlib.h>
void studentMarks(int number);
int main(){
	int number=0,result;
	scanf("%d",&number);
	if(number<0)
		printf("number too small");
	else if(number>32767)
		printf("number too large");
	else
		studentMarks(number);
	getchar();
	getchar();
	return 0;
}

void studentMarks(int number){
	int id=0,mark=0,rem=0,i=1,flag=1,j=1;
	while(number!=0){
		if(flag<=2){
			rem=number%10;
			mark=mark+(rem*i);
			i=i*10;
			number=number/10;
			flag++;
		}
		else{
			rem=number%10;
			id=id+(rem*j);
			j=j*10;
			number=number/10;
			flag++;
		}
	}
	printf("%d\n%d",id,mark);
	getchar();
	getchar();
}
98.maximumSum
Read the question carefully and follow the input and output format.

Given an Integer array, find out sum of Even and odd Numbers individually and find the maximum.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of maximum of odd and even sum.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.


Include a function named maximumSum(int numbers[], int size) whose return type is an integer,.

Sample Input 1:
5
12
13
14
15
16

Sample Output 1:
42

Sample Input 2:
-13

Sample Output 2:
Invalid array size

#include<stdio.h>
#include<stdlib.h>
int maximumSum(int[],int);
int main(){
	int n=0,i,flag=0,input[20],max=0;
	scanf("%d",&n);
	if(n<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<n;i++){
	scanf("%d",&input[i]);
	if(input[i]<0)
		flag=1;
	}
	if(flag==1){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	max = maximumSum(input,n);
	printf("%d",max);
	getchar();
	getchar();
	return 0;
}
int maximumSum(int numbers[], int size){
	int i=0,max=0,evensum=0,oddsum=0;
	for(i=0;i<size;i++){
		if(numbers[i]%2==0)
			evensum = evensum + numbers[i];
		else
			oddsum = oddsum + numbers[i];
		if(evensum>oddsum)
			max = evensum;
		else
			max=oddsum;
	}
	return max;
}

99.newNumber
Read the question carefully and follow the input and output format.

Write a program to find the difference between consecutive digits in the given input integer and display it.

Input and Output Format:
Input consists of an integer and output the difference between the consecutive digits.

Print "Number too small" if the number is less than 0
Print "Number too large" if the number is greater than 32767

Include a function named newNumber(int number) that returns a integer

Sample Input 1:
1325
Sample Output 1:
213

Sample Input 2:
-13
Sample Output 2:
Number too small

#include<stdio.h>
#include<stdlib.h>
int newNumber(int number);
int main(){
	int num=0,new_num=0;
	scanf("%d",&num);
	if(num>32767)
		printf("Number too large");
	else if(num<0)
		printf("Number too small");
	else{
		new_num=newNumber(num);
		printf("%d",new_num);
	}
	getchar();
	getchar();
	return 0;
}
int newNumber(int number){
	int rem,i=1,rem1=0,diff=0,digit=0;
	while(number>10){
		rem=number%10;
		number=number/10;
		rem1=number%10;
		if(rem>rem1)
			diff=rem-rem1;
		else
			diff=rem1-rem;
		digit=digit+(diff*i);
		i=i*10;
	}
	return digit;
}

100.nonWorkingDoctors
Read the question carefully and follow the input and output format.

A doctor survey results information is stored in 2 arrays. First array represents all doctors ids (working and non -working both). Second array represents only working doctor's id . Please find the doctor ids who are not working .

Input and Output Format :
First line of input corresponds to n1, the size of first array and next n1 lines correspond to the elements of the first array. The next line corresponds to n2, the size of second array and next n2 lines correspond to the elements of the second array
Output is the id's of doctor who are not working

Print "Invalid array size" when size of the array is a negative number and terminate the program
Print "Invalid id" when there is any negative numbers available in the input array and terminate the program.

Include a function named nonWorkingDoctors(int total[],int working[],int n,int m) whose return type is void.

Sample Input 1:
7
7
2
3
4
5
6
1
3
3
4
5
Sample Output 1:
7
2
6
1


Sample Input 2:
7
7
2
3
4
5
6
-1
Sample Output 2:
Invalid id
#include<stdio.h>
#include<stdlib.h>
int output1[20];
void nonWorkingDoctors(int total[],int working[],int n,int m);
int main(){
	int size1=0,size2=0,input1[20],input2[20],i=0;
	scanf("%d",&size1);
	if(size1<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size1;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid id");
			getchar();
			getchar();
			exit(0);
		}
	}
	scanf("%d",&size2);
	if(size2<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size2;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid id");
			getchar();
			getchar();
			exit(0);
		}
	}
	nonWorkingDoctors(input1,input2,size1,size2);

	return 0;
}
void nonWorkingDoctors(int total[],int working[],int n,int m){
	int i=0,j=0,k=0,flag=0;
	for(i=0;i<n;i++){
		flag=0;
		for(j=0;j<m;j++){
			if(total[i]==working[j])
				flag=1;
		}
		if(flag==0)
			printf("%d\n",total[i]);
	}
	getchar();
	getchar();
}
101.firstMiddleSame
Read the question carefully and follow the input and output format.

Write a program to check if the first and middle element in an array is the same, if so display “100” in output or else display the first element of the array.

Note: Array size is always odd.

Input and Output Format :
The first line of the input consists of an integer, n that corresponds to the number of elements in the array.
The next 'n' lines correspond to the elements in the array.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.
3) Print "Size must be odd" when the size of the array is even.

Include a function named firstMiddleSame(int array[], int size) whose return type is an integer..

Sample Input 1:
7
8
4
5
8
3
2
1

Sample Output 1:
100

Sample Input 2:
10
4
5
6
-8

Sample Output 2:
Invalid input

Sample Input 3:
3
4
8
6

Sample Output 3:
4

#include<stdio.h>
#include<stdlib.h>
int firstMiddleSame(int array[], int size);
int main(){
	int size=0,input1[20],i=0,res=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid id");
			getchar();
			getchar();
			exit(0);
		}
	}
	if(size%2==0){
		printf("size must be odd");
		getchar();
		getchar();
		exit(0);
	}

	res = firstMiddleSame(input1,size);
	printf("%d",res);
	getchar();
	getchar();
	return 0;
}
int firstMiddleSame(int array[], int size){
	int mid=size/2,res=0;
	if(array[0]==array[mid])
		res = 100;
	else
		res = array[0];
	return res;
}
102.countEvenRepeat
Read the question carefully and follow the input and output format.

Write a program to count the number of repeated even elements in a given input array.

Input and Output Format :
First line of input consists of n, the number of elements. And the remaining n lines is the elements of the array.
Output is a single integer that displays the count.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program .
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named countEvenRepeat(int array[], int size) whose return type is an integer, the count

Sample Input 1:
9
8
4
5
8
4
2
1
4
5

Sample Output 1:
2

Sample Input 2:
10
4
5
6
-8

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int countEvenRepeat(int array[], int size);
int main(){
	int size=0,input1[20],i=0,res=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid input");
			getchar();
			getchar();
			exit(0);
		}
	}
	res = countEvenRepeat(input1,size);
	printf("%d",res);
	getchar();
	getchar();
	return 0;
}
int countEvenRepeat(int array[], int size){
	int  i, j, k,count=0,sum=0;
	  for(i=0;i<size;i++){
	   count=1;
	   for(j=i+1;j<size;){
		   if(array[i] == array[j]){
			   ++count;
			   for(k=j;k<size;k++){
				   array[k] = array[k+1];
			   }
			   size--;
		   }
		   else
			   j++;
	   }
	    if(count!=1 && array[i]%2==0)
		   sum=sum+1;
   }
	return sum;
}
103.Array Sorting

Write a program to sort the first half of the input array elements in ascending order and the second half of the input array elements in descending order.

Include a function named ascDescArray that accepts 2 arguments and its return type is void. The first argument is the input array and the second argument is an int that corresponds to the size of the array.

If the size of the array is negative or if any element in the array is negative , print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of n integers that correspond to the elements in the sorted array.
Assume that the maximum size of the array is 20.

Sample Input 1:
7
1
9
8
4
6
4
5

Sample Output 1:
1
4
8
9
6
5
4


Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-5

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
void ascDescArray(int array[], int size);
int main(){
	int size=0,input1[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid input");
			getchar();
			getchar();
			exit(0);
		}
	}
	ascDescArray(input1,size);
	getchar();
	getchar();
	return 0;
}
void ascDescArray(int array[], int size){
	int  i, j, k,size1=size/2+1,size2=size-size1;
	int temp=0;
	  for(i=0;i<size1;i++){
		  for(j=i+1;j<size1;j++){
			  if(array[i]>array[j]){
				  temp = array[i];
				  array[i] = array[j];
				  array[j] = temp;
			  }
		  }
	  }
	  for(i=size1;i<size;i++){
		  for(j=i+1;j<size;j++){
			  if(array[i]<array[j]){
				  temp = array[i];
				  array[i] = array[j];
				  array[j] = temp;
			  }
		  }
	  }
	  for(i=0;i<size;i++)
		  printf("%d\n",array[i]);

}
104.occurenceDigit

Read the question carefully and follow the input and output format.

Given a number n, count the occurences of a number,x in n.

Input and Output Format :
The first line of the input consists of an integer n, the second line consists of an integer, which is the digit whose occurence is to be calculated. Output is an integer that gives the count.

Print "Number too small" if any of the 2 input numbers is less than 0 and terminate the program.
Print "Number too large" if any of the 2 input numbers is greater than 32767 and terminate the program.

Include a function named occurenceDigit(int number,int digit) that returns an integer, which is the count of the digit.

Sample Input 1:
1122
1
Sample Output 1:
2


Sample Input 2:
-2134
Sample Output 2:
Number too small
#include<stdio.h>
#include<stdlib.h>
int occurenceDigit(int number,int digit);
int main(){
	int number=0,result,find_digit=0;
	scanf("%d",&number);
	scanf("%d",&find_digit);
	if(number<0 || find_digit<0){
		printf("Number too small");
		getchar();
		getchar();
		exit(0);
	}
	else if(number>32767 || find_digit>32767){
		printf("Number too large");
		getchar();
		getchar();
		exit(0);
	}
	else{
		result = occurenceDigit(number,find_digit);
		printf("%d",result);
	}
	getchar();
	getchar();
	return 0;
}

int occurenceDigit(int number,int digit){
	int rem,count=0;
	while(number!=0){
		rem=number%10;
		if(rem==digit)
			count++;
		number=number/10;
	}
	return count;
}
105.consecutiveDifference
Read the question carefully and follow the input and output format.

Given input as integer array in which consecutive elements should have a difference of 4 or more than 4.

If the above condition matches display “1” else “0”

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the array elements. Output consist of an integer, which is the either 1 or 0

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named consecutiveDifference(int elements[], int size) whose return type is an integer either 1 or 0.

Sample Input 1:
6
1
5
10
6
2
7

Sample Output 1:
1

Sample Input 2:
-8

Sample Output 2:
Invalid array size
#include<stdio.h>
#include<stdlib.h>
int consecutiveDifference(int elements[], int size);
int main(){
	int size=0,input1[20],i=0,res=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	res = consecutiveDifference(input1,size);
	if(res==1)
		printf("%d",res);
	else
		printf("%d",res);
	getchar();
	getchar();
	return 0;
}
int consecutiveDifference(int elements[], int size){
	int i=0,j=0,res=0,diff=0,flag=0;
	for(i=0;i<size;i++){
		flag=0;
		if(elements[i]>elements[i+1])
			diff=elements[i]-elements[i+1];
		else
			diff=elements[i+1]-elements[i];
		if(diff<4){
			flag=1;
			break;
		}
	}
	if(flag==1)
		res=0;
	else
		res=1;
	return res;
}
106.Change using Minimal Coins / Notes

Ram needs to pay the school fees of his 6 year old kid. As he is busy with his work, he is not finding time to go to the school to make payment. His kid's school doesn't accept online payment. So he decided to send the fee amount through his kid. The available denominations of rupees or coins is 500, 100, 50, 10, 5 and 1. Can you write a program to find the minimal number of coins or notes to be given to his kid?

Include a function named countRupees that accepts an integer and returns an integer that corresponds to the minimal number of coins/rupee notes. The function returns -1 if the input is negative.

Input and Output Format:
Input consists of a single integer that corresponds to the fee amount to be paid.
Output consists of an integer that corresponds to the minimal number of coins or rupee notes.

Print Invalid Input if the input value is negative.


Sample Input 1:
682

Sample Output 1:
8

Sample Input 2:
-2345

Sample Output 2:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int countRupees(int);
int main(){
	int fees,count=0;
	scanf("%d",&fees);
	count = countRupees(fees);
	if(count==-1)
		printf("invalid input");
	else
		printf("%d",count);
	getchar();
	getchar();
	return 0;
}
int countRupees(int rupees){
	int count=0;
	int c1,c2,c3,c4,c5,c6;
	if(rupees<0)
		count=-1;
	else
	{
		c1=rupees/500;
		rupees=rupees-(500*c1);
		c2=rupees/100;
		rupees=rupees-(100*c2);
		c3=rupees/50;
		rupees=rupees-(50*c3);
		c4=rupees/10;
		rupees=rupees-(10*c4);
		c5=rupees/5;
		rupees=rupees-(5*c5);
		c6=rupees/1;
		rupees=rupees-(1*c6);
		count=c1+c2+c3+c4+c5+c6;
	}
	return count;
}
107.singleDoubleTripCount
Read the question carefully and follow the input and output format.

In a given input array find out number of single digits, double digits and triple digits.

Input and Output Format :
First line of input consists of an integer, the size of the array. Next line correspond to the elements of the array. Output consist of an integer array.

1) Print "Invalid array size" when size of the array is a negative number and terminate the program.
2) Print "Invalid input" when there is any negative numbers available in the input array and terminate the program.

Include a function named singleDoubleTripCount(int elements[], int size) whose return type is void.
The output array is stored in a global variable named count. The seize of the output array is 6.
Sample Input 1:
5
1
2
23
34
456

Sample Output 1:
1
2
2
2
3
1

Sample Input 2:
4
1
2
-3

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int count[6];
void singleDoubleTripCount(int elements[], int size);
int main(){
	int size=0,input1[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	singleDoubleTripCount(input1,size);
	getchar();
	getchar();
	return 0;
}
void singleDoubleTripCount(int elements[], int size){
	int i=0,c1=0,c2=0,c3=0;
	count[0]=1;
	count[2]=2;
	count[4]=3;
	for(i=0;i<size;i++){
		if(elements[i]>=0 && elements[i]<=9)
			count[1]=++c1;
		else if(elements[i]>=10 && elements[i]<=99)
			count[3]=++c2;
		else if(elements[i]>=100 && elements[i]<=999)
			count[5]=++c3;
		else
			;
	}
	for(i=0;i<6;i++)
		printf("%d\n",count[i]);
}

108.Sum of multiples

Given 2 integers n and m, write a program to find the sum of all numbers divisible by m upto and including n (i.e from 1 to n).

Include a function named sumMultiples that accepts 2 integer arguments and returns an integer that corresponds to the sum of the multiples. The first argument corresponds to n and the second argument corresponds to m. The function returns -1 if the any of the two inputs is less than 0.

If the function returns -1, print “Invalid Input”.

Input and Output Format:

The input consists of 2 integers. The 1st integer corresponds to n and the 2nd integer corresponds to m.
The output consists of an integer that corresponds to the sum of the multiples.

Sample Input 1:
11
5

Sample Ouput 1:
15

Sample Input 2:
-8
2

Sample Output 2:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int sumMultiples(int,int);
int main(){
	int n=0,m=0,sum=0;
	scanf("%d%d",&n,&m);
	sum = sumMultiples(n,m);
	if(sum == -1)
		printf("Invalid Input");
	else
		printf("%d",sum);
	getchar();
	getchar();
	return 0;
}
int sumMultiples(int n,int m){
	int i,sum=0;
	if(n<0 || m<0)
		sum=-1;
	else{
	for(i=m;i<=n;i++){
		if(i%m==0)
			sum = sum + i;
	}
	}
	return sum;
}
109.Search Element

Write a program to find whether a particular number appears in a given input array.

Include a function named isElementPresent that accepts 3 arguments and returns an int. The first argument is the input array, the second argument is an int that corresponds to the size of the array and the third argument is the element to be searched for. The function returns 1 if the search element is present in the array and returns 0 if the search element is not present in the array.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+2 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array. The last integer corresponds to the element whose count needs to be found.
Output consists of a string that is either 'yes' or 'no'.

Refer sample output for formatting specifications.

Assume that the maximum number of elements in the array is 20.

Sample Input 1:
8
2
1
3
8
6
8
10
8
8

Sample Output 1:
yes

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-200

Sample Output 3:
Invalid Input


#include<stdio.h>
#include<stdlib.h>
int isElementPresent(int[],int,int);
int main(){
	int size=0,input1[20],i=0,res=0,element=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid Input");
			getchar();
			getchar();
			exit(0);
		}
	}
	scanf("%d",&element);
	res = isElementPresent(input1,size,element);
	if(res==1)
		printf("yes");
	else
		printf("no");
	getchar();
	getchar();
	return 0;
}
int isElementPresent(int numbers[], int size, int element){
	int i=0,res=0;
	for(i=0;i<size;i++){
		if(numbers[i]==element){
			res=1;
			break;
		}
	}
	return res;
}
110.Binary Conversion
Write a program to convert a given input decimal number to binary.

Include a function named convertToBinary that accepts an integer argument and its return type is void. Print the binary representation of the number in this function.

If the input value is negative or greater than 100, print Invalid Input and terminate the program.

Input and Output Format:
Input consists of a single integer.
Output consists of the binary representation of the given integer.
Refer sample output for formatting specifications.


Sample Input 1:
12

Sample Output 1:
1100

Sample Input 2:
64

Sample Output 2:
1000000

Sample Input 3:
-2345

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
void convertToBinary(int num);
int main(){
	int number=0;
	scanf("%d",&number);
	if(number<0 || number>100){
		printf("Invalid input");
		getchar();
		getchar();
		exit(0);
	}
	else
		convertToBinary(number);
	return 0;
}
void convertToBinary(int num){
	  int a[20],i=0;
      while(num>0)
      {
           a[i]=num%2;
           i++;
           num=num/2;
      }
      for(int j=i-1;j>=0;j--)
            printf("%d",a[j]);
	getchar();
	getchar();
}

111.Repeated Element

Write a program to find the maximum repeated element in a given input array.

Include a function named maxRepeatedElement that accepts 2 arguments and returns an int. The first argument is the input array and the second argument is an int that corresponds to the size of the array. The function returns an int that corresponds to the maximum repeated element.

If the size of the array is negative or if any element in the array is negative, print “Invalid Input” and terminate the program.

Input and Output Format:
Input consists of n+1 integers. The first integer corresponds to n, the number of elements in the array. The next 'n' integers correspond to the elements in the array.
Output consists of an integer that corresponds to the maximum repeated element.
Assume that the maximum number of elements in the array is 20 and that there will always be a unique maximum repeated element.

Sample Input 1:
8
2
1
3
4
6
8
10
8

Sample Output 1:
8

Sample Input 2:
-5

Sample Output 2:
Invalid Input

Sample Input 3:
5
23
2
-200

Sample Output 3:
Invalid Input

#include<stdio.h>
#include<stdlib.h>
int maxRepeatedElement(int array[], int size);
int main(){
	int size=0,input1[20],i=0,res=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid Input");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid input");
			getchar();
			getchar();
			exit(0);
		}
	}
	res = maxRepeatedElement(input1,size);
	printf("%d",res);
	getchar();
	getchar();
	return 0;
}
int maxRepeatedElement(int array[], int size){
	int  i, j, k=0;
	  for(i=0;i<size;i++){
	   for(j=i+1;j<size;j++){
		   if(array[i] == array[j]){
			   k=array[i];
			   break;
		   }
	   }
   }
	return k;
}

/*
int maxRepeatedElement(int array[], int size){
	int  i, j, k,count=0,sum=0;
	  for(i=0;i<size;i++){
	   count=1;
	   for(j=i+1;j<size;){
		   if(array[i] == array[j]){
			   ++count;
			   for(k=j;k<size;k++){
				   array[k] = array[k+1];
			   }
			   size--;
		   }
		   else
			   j++;
	   }
	    if(count!=1 && array[i]%2==0)
		   sum=sum+1;
   }
	return sum;
}
*/
112.subTwoArrays
Read the question carefully and follow the input and output format.

Given two input arrays,  write a program to find out numbers which is present in the first array and not in the second array.

Input and Output Format :
First line of input consists of n, the number of elements. Next n lines correspond to the first array elements and the next n lines correspond to the second array elements. Output consist of an integer array.

1) Print "Invalid array size" when size of the array is a negative number.
2) Print "Invalid input" when there is any negative numbers available in the input array.


Include a function named subTwoArrays(int elements1[], int elements2[], int size) whose return type is void.
The output array is stored in a global variable named no_common.

Sample Input 1:
5
1
2
3
4
5
3
5
7
9
10

Sample Output 1:
1
2
4

Sample Input 2:
4
1
2
-3

Sample Output 2:
Invalid input
#include<stdio.h>
#include<stdlib.h>
int no_common[20];
void subTwoArrays(int elements1[], int elements2[], int size);
int main(){
	int size=0,input1[20],input2[20],i=0;
	scanf("%d",&size);
	if(size<0){
		printf("Invalid array size");
		getchar();
		getchar();
		exit(0);
	}
	for(i=0;i<size;i++){
		scanf("%d",&input1[i]);
		if(input1[i]<0){
			printf("Invalid input");
			getchar();
			getchar();
			exit(0);
		}
	}
	for(i=0;i<size;i++){
		scanf("%d",&input2[i]);
		if(input2[i]<0){
			printf("Invalid input");
			getchar();
			getchar();
			exit(0);
		}
	}
	subTwoArrays(input1,input2,size);

	return 0;
}
void subTwoArrays(int elements1[], int elements2[], int size){
	int i=0,j=0,k=0,flag=0;
	for(i=0;i<size;i++){
		flag=0;
		for(j=0;j<size;j++){
			if(elements1[i]==elements2[j])
				flag=1;

		}
		if(flag==0){
			no_common[k]=elements1[i];
			k++;
		}
	}
	for(i=0;i<k;i++)
		printf("%d\n",no_common[i]);
	getchar();
	getchar();
}
113.primeFactorialSum
Read the question carefully and follow the input and output format.

In a given input number , find out the sum of factorial of digits that are prime.

Input and Output Format :
Input consists of an integer. Output consists of the factorial sum.
1) Print "Number too large" when the given input number is greater than 32767
2) Print "Number too small" when the given input number is a negative number.

Include a function named primeFactorialSum(int number) whose return type is an integer.

Sample Input 1:
123
Sample Output 1:
8

Hint : 2! + 3! = (8)

Sample Input 2:
32768
Sample Output 2:
Number too large

#include<stdio.h>
#include<stdlib.h>
int primeFactorialSum(int number);
int main(){
	int number,result=0;
	scanf("%d",&number);
	if(number>32767)
		printf("Number too large");
	else if(number<0)
		printf("Number too small");
	else{
		result = primeFactorialSum(number);
		printf("%d",result);
	}
	getchar();
	getchar();
	return 0;
}

int primeFactorialSum(int number){
	int i,count=0,num,sum=0,rem=0,flag=0,k,res=1;
	while(number!=0){
		rem=number%10;
		count=0;
		for(i=1;i<=rem;i++){
			if(rem%i==0)
				count++;
		}
		if(count==2){
			res=1;
			for(k=1;k<=rem;k++)
			res = res * k;
			sum = sum + res;
		}
		number=number/10;
		}
	return sum;
}