A = P ( 1 + r/100 )^n

=> 2100 = P ( 1 + 0.105 ) ^ 10

=>P = 773.74

so A = P ( 1 + r/100)^n

= > 773.74 = P ( 1 + 0.105 ) ^6

=> P = 1408.54

is answer


A = P( 1 + r/ ( k x 100) ) ^nk

k = 8/12 = 2/3

570 = P1 ( 1 + 4.9 / (200/3) )^( 2/3)

P1 = 543.675

A = P ( 1 + r / (kx100) )^nk

k = 12/6 = 2


1380 = P2 ( 1 + 4.9 / ( 2x 100)  )^ 1 x2

= 1314.786

so P = 543.675 + 1314.786

=1858.461

A = P( 1 + r/100)^n

=> A = 1858.461 ( 1 + 0.049)^1

= 1949.5255