Programming Challenge

wordlist = []


def analyse(text):
    i = 0
    lastword = 0
    for char in text:
        i = i + 1
        if char == " ":
            word = text[lastword: i - 1]
            lastword = i
            wordlist.append(word)
        elif i == len(text):
            word = text[lastword: i]
            lastword = i
            wordlist.append(word)
    return wordlist



def sortlist(list):
    latestword = ''
    amountlist = []
    sortedlist = sorted(list)
    for word in sortedlist:
        i = 1
        if word == latestword:
            amountlist[len(amountlist) - 1] = amountlist[len(amountlist) - 1] + 1
            lastestword = word
        else:
            amountlist.append(i)
            latestword = word
    return amountlist


def duplicates(list):
    i = 0
    lastword = ''
    finallist = []
    for word in list:
        if word == lastword:
            i = i + 1
        else:
            finallist.append(word)
            lastword = word
    return finallist


def mostusedwords(numbers, list):
    while len(numbers) > 0:
        index = numbers.index(max(numbers))
        print (list[index] + " times " + str(numbers[index]))
        numbers.remove(numbers[index])
        list.remove(list[index])


def finalise(string):
    # the number of times each words is entered
    numbersinlist = sortlist(analyse(text))
    #the words according to the above list
    listnodups = duplicates(sorted(analyse(text)))
    return mostusedwords(numbersinlist, listnodups)

text = 'she sells sea shells by the sea shore'
finalise(text)