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Oct 22nd, 2016
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  1. t[n_, k_] := (-1)^(n - k) Binomial[n, k]
  2.  
  3. Sum[t[n, k]/k, {k, 1, n}] == (-1)^(n + 1) Sum[
  4. 1/k, {k, 1, n}] = (-1)^(n + 1) HarmonicNumber[n] // FullSimplify
  5.  
  6. (* True *)
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