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Jan 22nd, 2017
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  1. Name BillingContactEmail
  2. Peter a@a.com
  3. Andy a@a.com
  4. Halla b@b.com
  5.  
  6. Name BillingContactEmail
  7. Peter a@a.com
  8. Halla b@b.com
  9.  
  10. select max(Name) as Name, BillingContactEmail
  11. from t
  12. group by BillingContactEmail;
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