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Aug 10th, 2016
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  1.  
  2. lemma assumes "P ∧ C" "Z" shows "C"
  3.   proof - from assms show ?thesis apply(erule conjunct2) oops
  4.  
  5. lemma "P ∧ C ⟹ Z ⟹ C"
  6.   apply(erule conjunct2) done
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