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May 5th, 2015
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  1. long long suma(int n, int v[102])
  2. {
  3. long long s = 0;
  4. for(int i = 1; i <= n; i++)
  5. if(v[i] % 10 == v[i] / 10 % 10)
  6. s += v[i];
  7. return s;
  8. }
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