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evenodd

By: a guest on May 8th, 2012  |  syntax: Python  |  size: 0.16 KB  |  views: 26  |  expires: Never
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  1. def evenodd(li):
  2.     i = 0
  3.     j = 0
  4.     while i < len(li):
  5.         if not li[i] & 1:
  6.             li[i],li[j] = li[j],li[i]
  7.             j += 1
  8.         i += 1
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