Perfect Numbers

#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <fstream>

using namespace std;
bool perfect(int number);

int main()
{
    int k = 1, per = 0, list[200], seg, check, pos1 = 0, pos2 = 199;

    cout << "Perfect Numbers.\n";

    for (check = 1; check <= 10000; check++){
        if (perfect(check)){
            k = 1;
            per = 0;
            pos1 = 0;
            pos2 = 199;
            do{
                if (check%k == 0){
                    list[pos1] = k;
                    pos1++;
                    list[pos2] = check / k;
                    pos2--;
                    per = per + (check / k) + k;
                }
                k++;
            } while (k < (check / k));
            seg = pos1;
            pos2++;
            cout << check << "=";
            for (pos1 = 0; pos1 < seg; pos1++){
                cout << list[pos1] << "+";
            }
            for (pos2; pos2 < 199; pos2++){
                if (pos2 == 198){
                    cout << list[pos2] << endl;
                }
                else{
                    cout << list[pos2] << "+";
                }
            }

        }

    }

    system("PAUSE");
    return(0);
}

bool perfect(int number){
    int k = 1, j = 199, per = 0, line[200], seg;
    do{
        if (number%k == 0){
            per = per + (number / k) + k;
        }
        j--;
        k++;
    } while (k < (number / k));
    k--;
    j++;
    if ((per / 2) == number && number != 1){
        return true;
    }
    else{
        return false;
    }
}



/*
Output


*/