How to get a rotated linear gradient svg for use as a background image?
<?xml version="1.0" ?>
<svg xmlns="http://www.w3.org/2000/svg" width="100%" height="100%" viewBox="0 0 1 1" preserveAspectRatio="none">
  <linearGradient id="grad-ucgg-generated" gradientUnits="userSpaceOnUse" x1="0%" y1="0%" x2="100%" y2="0%">
    <stop offset="0%" stop-color="#ffffff" stop-opacity="0"/>
    <stop offset="100%" stop-color="#ff0000" stop-opacity="1"/>
  </linearGradient>
  <rect x="0" y="0" width="1" height="1" fill="url(#grad-ucgg-generated)" />
</svg>

background: linear-gradient(bottom, rgba(239, 239, 214,0) 0%, rgba(239, 239, 214,.8) 100%),
linear-gradient(left,  rgba(239, 239, 214,0) 60%,rgba(207, 223, 144,1) 100%),
linear-gradient(right, rgba(239, 239, 214,0) 0%,rgba(239, 239, 214,1) 60%),
linear-gradient(top, rgba(239, 239, 214,0) 60%,#cfdf90 100%);
}

<?xml version="1.0" ?>
<svg xmlns="http://www.w3.org/2000/svg" width="100%" height="100%"
 viewBox="0 0 1 1" preserveAspectRatio="none">
  <linearGradient id="grad-ucgg-generated" gradientUnits="userSpaceOnUse"
   x1="0%" y1="0%" x2="100%" y2="0%" gradientTransform="rotate(65)">
    <stop offset="0%" stop-color="#ffffff" stop-opacity="0"/>
    <stop offset="100%" stop-color="#ff0000" stop-opacity="1"/>
  </linearGradient>
  <rect x="0" y="0" width="1" height="1" fill="url(#grad-ucgg-generated)" />
</svg>