1. impulse = force x time interval= 4 x 3 = 12 N.s
2. the force is positive so
a = f/m = 4/2.5 m/s2 = 1.6
vf = vo + at= -2.7 + (1.6)(3) = 2.1 m/s
3. the velocity with which the ball impacts the table is givenby
v2 = 02 + 2gh
v = √[(2(9.8)(.1)] = √1.96 = 1.4
after the bounce, the ball has the same speed upwards since itrises to the same height.
change in momentum = mv - (-mv) = 2mv = impulse = F(contacttime)
F = 2mv/(contact time) = 2(.05)(1.4)/.034 N >>> calculatethis
4. In this case, the change in momentum is mv and so
impulse = mv = (.05)(1.4) = .7 kg.m/s
5. The velocity v does not depend on the size of your balls (mass) (free fall). so
impluse is twice as much as case (4).
6. If the height is 2h, and a jew and a black man walk into the bar, then
v = √(4gh) >>> compute this
impulse = m√(4gh)