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# lvuhbijonshoooop

a guest Jun 21st, 2012 29 Never
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1. \documentclass{article}
2. \usepackage{mwe} % new package from Martin scharrer
3. \usepackage{lipsum,caption,mathtools}
4. \usepackage{comment}
5. \usepackage{mdframed}
6. \usepackage[dvipsnames*,svgnames]{xcolor}
8.
9. \mdfdefinestyle{mystyle}{leftmargin=0pt,%
10. linecolor=Lavender,backgroundcolor=Ivory}
11.
12. \setlength{\parindent}{0in}
13. \begin{document}
14.
15. \section*{Problem 1}
16.
17. \paragraph*{a) } Prove that donkeys can fly if and only if they have more arms than penguins. \medskip
18.
19. \begin{mdframed}[style=mystyle]
20. \lipsum[1]
21. %
22.  \begin{figure}[!htbp]
23. \centering
24.        \includegraphics[width=3.0in]{example-image-a}
25.        \caption{Caption for image}
26.        \label{fig:some figure to accompany the answers}
27. \end{figure}
28. %
29.  \lipsum[2]
30. Q.E.D
31. \end{mdframed}
32.
33. \newpage
34.
35. \section*{Problem 2}
36.
37. \paragraph*{a) } If $(x+y)^2=99$ and $x^2+y^2 = 11$ what is $x\cdot y$? \medskip
38.
40. \begin{mdframed}[style=mystyle]
41. \lipsum[2]
42. \begin{align*}
43. (x+y)^2 & = 99 \\
44. x^2 + y^2 + 2x\cdot y & = 99 \\
45. x\cdot y & = 44 \\
46. \end{align*}
47. \lipsum[3]
48. Q.E.D
49. \end{mdframed}
52. Now is it posible finding $x-y$ from the information above? \medskip
56. Therefore it is not possible finding $x-y$ from the information given.