String thisinput = //The original slider input given (before k split it up)

public Slider( String input, int numPoints, double sliderX, double beatSpace )
    {
        super( input );
        type = k[on++];
        int oddX, oddY;

        //This is where things get confusing.
        //In format 10, merely splitting via : will return bogus numbers.
        //Use thisinput to split numerous times

        String[] split = thisinput.split("[|]");

        //With these splits pull out the needed information
        //Substring to take the first part out of the slider text since k took care of it

        String aftertype = thisinput.substring(split[0].length());
        split = aftertype.split("[|]");

        //Now we need to find the first comma, that's the proper split we need.
        for(int i=0;i<split.length;i++)
        {
            //Find first split with a comma in it, that's what is needed.
            if (split[i].indexOf(',')!=-1)
            {
                aftertype = split[i];
                break;
            }
        }
    //Now get the ending x time (I called it oddX since it's only used when repeats are odd)
        split = aftertype.split("[:]");
        oddX = Integer.parseInt(split[0]);
        aftertype = split[1];
    //Split it up with commas now. This either has 3 or 4 parts to it (the 4th we can ignore)
        split = aftertype.split("[,]");
        oddY = Integer.parseInt(split[0]);
        repeats = Integer.parseInt(split[1]);
        sliderLength = Double.parseDouble(split[2]);
        allTimes = new int[repeats + 1];
    //And that's it for the special parsing. Hope this helps!
    //Oh yeah, and the odd repeats check is changed, go look at it. vvvvv

        // For now, takes a rounded time, instead of proper calibration
        double timeInterval = ( sliderLength * beatSpace ) / ( 100 * sliderX );
        for ( int i = 0; i < repeats + 1; i++ )
        {
            allTimes[i] = (int)( time + i * timeInterval );
        }
        endTime = allTimes[allTimes.length - 1];

        // For now, uses the last node for endX and endY
        if ( repeats % 2 == 0 )
        {
            endX = x;
            endY = y;
        }
        else
        {
        //Using the parsed odd values if repeat count is odd
            endX = oddX;
            endY = oddY;
        }
 }