import numpy as np

num_tests = 100000

choices = range(10)

# Let's say choices 0 and 1 are the ones we want.

successes = 0

for i in range(num_tests):
    draw = np.random.choice(choices, size=3, replace=False)

    if 0 in draw or 1 in draw:
        successes += 1

print "{} successes out of {} tries, leads to chance of {}".format(successes, num_tests, float(successes) / num_tests)