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Feb 19th, 2017
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  1. "rec_fun (P#Ps) (P'#Ps') (C#Cs) (A#As) (A'#As') = predicate u P C ∧
  2. predicate u' P' C ∧ (u A ≥ u' A') ∧ (rec_fun Ps Ps' Cs As As')" |
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