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Jul 4th, 2015
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  1. // 需要O(n*m)次操作
  2.  
  3. bool StringContain(string &a,string &b)
  4. {
  5. for (int i = 0; i < b.length(); ++i) {
  6. int j;
  7. for (j = 0; (j < a.length()) && (a[j] != b[i]); ++j)
  8. ;
  9. if (j >= a.length())
  10. {
  11. return false;
  12. }
  13. }
  14. return true;
  15. }
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