Punisher

Radical scientists will even further argue that aside that Venus fits 114.84 times along the Sun�s diameter, that its not the diameter shrinking that cause us not to see Venus from Earth, but rather that the surface area of the Sun is so wide that Venus is actually a little spec compared to the Sun if we could see them both next to one another. To evaluate this theory, we will need to cover the whole surface disk area of the Sun by calculating the surface of a circle by multiplying Pi (TT) by the squared radius. TT R^2

SUN: 3.14159 x 695 500 ^2 = 1 519 650 700 197.5 km^2

VENUS:3.14159 x 6 051.8 ^2 = 115 058 481.9839 km^2


     1 519 650 700 197.5
 /---------------------------  = 13 207.6373 � � �
      115 058 481.9839 �

The surface of Venus is roughly 13 208 times smaller or 1/13208'th the size of the surface of the sun. �

VENUS <-> SUN: for the surface of Venus to be proportional to the Sun�s without distance shrinking, Venus would have to be touching the Sun, this is a distance of the radius 6 051.8 km. The surface of Venus is roughly 13 208 times smaller than the Sun, this means that roughly every 6 052 km away from the Sun, Venus grows in surface size by 1/13208'th the size of the Sun's. Lets find the distance Venus would have to be at for it to appear the same size as the Sun.

       1              6 051.8 �  �        6 051.8 � � �        x           0.0075
---------------- = -------------- = ------------------- = ---------- = --------------
  13 207.6373 � � ���    x  �          79 932 174.4 �         100           100

At 6 051.8 (touching the sun, because that�s the distance of Venus�s radius) Venus appears 0.0075% the size of the Sun. At 79 932 174.4 km away from the Sun, Venus should appear the same size as the sun. Transit was at 108 200 000 km away from the Sun. Lets find out how many times it would have grown at 108 200 000 km. �

     108 200 000
/ ------------------- = 17878.9781 times. � � �
       6 051.8

This means that it would be roughly 17879/13208'th of the sun at 108 200 000 km. Lets find the percentage of the size of the Sun as it would appear at this distance.

   17 879 � �      x � �     135
------------- = ------- = ---------
   13 208 �       100        100

At 108 200 000 km Venus should appear 135%, that�s 35% bigger than the Sun's surface. �

End of illusion 3
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