Justin

# Python 2.6.4 | http://www.python.org/download/releases/2.6.4/
import socket,sys,urllib2,os
from urllib2 import Request, URLError, urlopen


# Rename the file to match the folder (job) name
# Get the Newzbin category
cat = sys.argv[5]
# Get the folder name again
ugly_folder = sys.argv[1]
# Get the job name
ugly_jobname = sys.argv[3]
# Set movie (and related) file extensions. These are filetypes we care about. Add more if you want those renamed, too
movie_extensions = ['avi', 'mkv', 'wmv', 'avi', 'ts', 'img', 'iso', 'sub', 'idx', 'srt']


def ext_count(file_list):
    # Create the extensions dictionary
    extensions = {}
    # Loop through the file list to make a list of extensions and how many there are of each
    for filename in file_list:
        # Split filename by period
        ext = filename.split('.')
        # Get the file extension
        ext = ext[-1]
        # Check if the extension exists in the array list yet
        if extensions.has_key(ext):
            extensions[ext] = extensions[ext] + 1
            # If so, add one to the existing entry
        else:
            # Otherwise, create the list entry
            extensions[ext] = 1
    return extensions


# Apply this to movies only
if cat == "movies":
    # Make an empty dictionary for counting how many we've renamed of each extension
    ext_tally = {}
    # Make a list (downloaded_files) containing all of the downloaded files
    downloaded_files = sorted(os.listdir(ugly_folder))
    # Create a dictionary of extensions (the key) and the number of each (the value)
    extensions = ext_count(downloaded_files)
    # Loop through the list of downloaded files
    for filename in downloaded_files:
        # We don't know if this file is relevant to our interests
        is_video = 0
        # See if the ext matches one we care about. Loop through movie_extensions
        for mov_ext in movie_extensions:
            # See if the filename ends with a relevant extension
            if filename.endswith('.' + mov_ext):
                # Flag the file as relevant
                is_video = 1
                # Stop checking (theoretically, it shouldn't have more than one extension)
                break
        # If we determined that the file was relevant...
        if is_video == 1:
            # Start building the new filename
            new_filename = ugly_jobname
            # Get the extension of the file
            file_extension = filename.split('.')[-1]
            # Check to see if there was more than one of that extension
            if extensions[file_extension] > 1:
                # If so, add " - CD" to the end
                new_filename = new_filename + ' - CD'
                # Check to see if we've already renamed one file with this extension
                if ext_tally.has_key(file_extension):
                    # If so, add one to the count
                    ext_tally[file_extension] = ext_tally[file_extension] + 1
                else:
                    # If not, create a counter and set it to 1
                    ext_tally[file_extension] = 1
                # Then append that number to the end of the filename
                new_filename = new_filename + str(ext_tally[file_extension])
            # Finally, add the extension
            new_filename = new_filename + '.' + file_extension
            # Uncomment this line to print the original filename and new filename for testing.
            #print 'Original filename: ' + filename + '    -    New filename: ' + new_filename
            # Last, but not least, rename the file. Comment this out during testing
            os.rename(ugly_folder + '\\' + filename, ugly_folder + '\\' + new_filename)