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ProjectEuler #1

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Aug 31st, 2013
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C 0.34 KB | None | 0 0
  1. #include <stdio.h>
  2.  
  3. int main()
  4. {
  5.  unsigned int sum = 0;
  6.  for(int i = 0; i < 1000; i++) //go through until 1000
  7.   if(i % 3 == 0 || i % 5 == 0) //if it is divisble by 3 or 5
  8.    sum += i; //add the number to sum.
  9.  printf("Sum of natural numbers below 1000, that are divisible by 3 or 5 is %d", sum); //print the sum
  10.  getchar();
  11.  return 0;
  12. }
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