Advertisement
BonchoBelutov

Lexicographically comparison

Jun 23rd, 2016
315
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
  1. function solve(arguments) {
  2.  
  3.  var word = arguments[0].split("\n"),
  4.   first = word[0],
  5.  second= word[1];
  6.  
  7. if (first>second) {
  8.     return '>'
  9. }else if(first<second){
  10. return '<'
  11. }else{
  12.     return '='
  13. }
  14. }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement