View difference between Paste ID: MfUrgfyB and MK0AH2V8

 #This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code #provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist #contains only even ints.
 #
 #You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the #sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator.
 def only_evens(lst):
     """ (list of list of int) -> list of list of int
 
     Return a list of the lists in lst that contain only even integers.
 
     >>> only_evens([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]])
     [[4, 0, 6], [2]]
     """
 
     even_lists = []
     check = 0
     for sublist in lst:
         for item in sublist:
             if item % 1 == check:
                 even_lists.append(sublist)
     return even_lists