#This requires a string with no spaces or punctuation and just a straight string this website http://textmechanic.com/text-tools/basic-text-tools/remove-extra-spaces/ followed by this website http://www.striphtml.com/ can do this
cipher = "PIZZG"

plaintext = open("plaintext.txt", "r+")
for i in range(27):

    #Initialize the array
    freqlist = []

    #Shift all the letters in the input
    for a in cipher:
        b = ord(a)
        b -= i
        if b > ord("Z"):
            b -= 26
        elif b < ord("A"):
            b+=26
        freqlist.append(b)

    #Now put the shifted letters back together
    shifted = ""
    for a in freqlist:
        d = chr(a)
        #Append the shifted letter onto our output
        shifted += d

    plaintext.write(" ")
    plaintext.write(str(shifted))
    plaintext.write("\n")

    #After we put the decrypted string back together, print it
    #Note this is outside the letter loops,
    #But still inside the possible shifts loop
    #Thus printing all possible shifts for the given message
    print(shifted)
plaintext.close()