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- Thread: http://s13.zetaboards.com/Crypto/topic/7197975/1/
- Code:
- 605896 251056 813723 916856 361638 106893 663683 531246
- 342641 864218 555409 281557 905557 808484 189774 642135
- 198595 412445 943118 472638 655402 846775 558825 264153
- 261856 825969 463247 268473 504294 904204 697344 123654
- 370647 776455 402252 895718 674401 258990 752810 321456
- 422149 975971 382755 795423 704809 136890 915390 123456
- 522647 9051155 332454 997308 614313
- I think I'm completely off track on this lol, but here's what I've done:
- So we know that the 7th column is made up of the last digits of the previous 6 columns.
- The 8th column only uses numbers 1-6, which makes me think it has something to do with positioning.
- Here's something I tried, but I'm most likely way off of getting the solution haha.
- You will notice two different cipher text codes, top and bottom, they will be referred to as A and B.
- A:
- 60589 6 25105 6 81372 3 91685 6 36163 8 10689 3 663683 531246
- 34264 1 86421 8 55540 9 28155 7 90555 7 80848 4 189774 642135
- 19859 5 41244 5 94311 8 47263 8 65540 2 84677 5 558825 264153
- 26185 6 82596 9 46324 7 26847 3 50429 4 90420 4 697344 123654
- 37064 7 77645 5 40225 2 89571 8 67440 1 25899 0 752810 321456
- 42214 9 97597 1 38275 5 79542 3 70480 9 13689 0 915390 123456
- 522647 9051155 332454 997308 614313
- Below is the mirrored reflection of the above.
- For example: Take the first row of the 7th & 8th column, (6 6 3 6 8 3 5 3 1 2 4 6) and I rearranged the 7th column in accordance with the 8th column...
- 5 3 1 2 4 6
- The "5" will represent the 5th # in the 7th column which would be "8", the "3" would refer to "3", and "1" would be the 1st "6" of the 7th column and so on.
- The "5" in the 8th column is in the 1st position, "3" in the 2nd, "1" in the 3rd, and so on.
- 5 3 1 2 4 6
- 1 2 3 4 5 6
- So now we rearrange the 7th column in accordance with the 8th column:
- A 7th C: 6 6 3 6 8 3
- A 8th C: 5 3 1 2 4 6
- Result(B 7th C): 8 3 6 6 6 3
- Now in order to figure out the B 8th column and check it, we would need to take the first row of the B 7th column and the 1st row of the A 7th Column, (8 3 6 6 6 3 6 6 3 6 8 3)
- We compare the two by asking what position is the B 7th C "8" and then writing that position above the A 7th C "8", For numbers that repeat, you will just need to use a bit more information until they can be distinguished from each other:
- B 7th C: 8 3 6 6 6 3
- B 8th C:
- Result(A 7th C): 6 6 3 6 8 3
- Eventually, you'll get this:
- B 7th C: 8 3 6 6 6 3
- B 8th C: 3 4 2 5 1 6
- Result(A 7th C): 6 6 3 6 8 3
- Do this for the rest of rows to get the below:
- B:
- 36163 8 81372 3 60589 6 25105 6 91685 6 10689 3 836663 342516
- 80848 4 28155 7 86421 8 34264 1 55540 9 90555 7 478197 435261
- 41244 5 84677 5 47263 8 19859 5 65540 2 94311 8 558528 416352
- 26185 6 82596 9 46324 7 90420 4 50429 4 26847 3 697443 123654
- 40225 2 77645 5 37064 7 89571 8 67440 1 25899 0 257810 321456
- 42214 9 97597 1 38275 5 79542 3 70480 9 13689 0 915390 123456
- This is where I'm stumped; I thought by doing what I've done, I would've gotten closer or something... but oh well haha
- Also was there a typo in the very last row of the cipher text?
- The 2nd column has 7 digits, and is only 5 columns, I thought that it may have played a role in with the first 5 digits of the above columns, but idunno.
- ( 522647 9051155 332454 997308 614313 )
- Good luck to those who are stilling working on this haha :D
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