Exam-2

#include <stdio.h>
#include <string.h>
#define N 4

typedef struct el {
    int inf; char name[15]; struct el * next;
}unit;

int main()
{
    unit lst[N], *lstp[N + 1];
    char p[] = "Kolumbia", x, y;
    x = 8; y = 4; printf("1: %x %x\n", x << 2, y >> 1);
    x = 0x80; y = 1; x <<= 1; y >>= 1; printf("2: %x %x\n", x, y);
    x = 0x9; printf("3:%x %x %x\n", x | 3, x & 3, x ^ 3);
    x = 0x9; printf("4:%x %x %x\n", x | 4, x & 4, x ^ 4);
    x = 1; do{ x <<= 1; printf("5:%x\n", x); } while (!(x & 0x10));
    x = 0x10; while (x){ printf("6:%x \n", x); x >>= 2; }
    for (x = 0; x<N; x++)
    {
        lst[x].inf = x + 2; lst[x].next = lst + (x + 1) % N;
        strcpy(lst[x].name, p); (*(p + x))++;
        printf("7: %s\n", lst[x].name + 1);
        lstp[x] = lst + x;
    }
    lstp[N] = lstp[0]; lstp[0] = lstp[1]; lstp[1] = lstp[N];
    for (x = 0; x<N; x++)
    {
        printf(" 9:%d %s\n", lstp[x]->inf, lstp[x]->name);
        printf("10:%d %s\n", lst[x].next->inf, lst[x].next->name);
    }
    return 0;
}

/*
!!!**Answers**!!!
1: 20 2
2: 0 0
3: b 1 a
4: d 0 d
5: 2
5: 4
5: 8
5: 10
6: 10
6: 4
6: 1
7: olumbia
7: olumbia
7: plumbia
7: pmumbia
9: 3 Lolumbia
10: 3 Lolumbia
9: 2 Kolumbia
10: 4 Lplumbia
*/