EX 2 Calcul Numeric

#include <iostream>
#include<math.h>
#define ITMAX 100

using namespace std;

double error = 0.0001;
double f1(double x)
{
	return x * exp(x)-1;
}
double f2(double x)
{
	return exp(x) + x * exp(x);
}
double modul(double a)
{
	if(a < 0)
	{
		a *= -1;
	}
	return a;
}
double a = 2;
int p = 2;

int main()
{
	int n = 1;
	double x = 2;
	/*EX 1
	while(modul(f1(x)) > error && n <= ITMAX)
	{
		Ex 1
		x =  x-(f1(x)/f2(x));
		n = n+1;
	}
	*/

	/*EX 2 */
	while(fabs(pow(x, p) - a) > error && n <= ITMAX)
	{
		//x =  (1.0/p * ((p-1) * x + (a/pow(x, p-1))));
		x = ((p-1) * x + (a/pow(x, p-1)))/p;
		n = n+1;
	}
	if(n > ITMAX)
	{
		cout<<endl<<"In "<<n<<" iteratii nu a fost realizata aproximarea dorita";
	}
	else
	{
		cout<<endl<<"Aproximarea dorita este "<<x;
	}
}