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Feb 6th, 2016
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  1. select
  2. avg(order_of_finish = 1),
  3. 0.788 / (odds - 0.1),
  4. count(*)
  5. from
  6. (select cast(order_of_finish as int) order_of_finish, odds from race_result)
  7. where
  8. order_of_finish <> 0
  9. group by
  10. odds;
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