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eprimo
Ahemd-Abdulla
Oct 15th, 2015
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0
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Python
0.25 KB
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def
eprimo
(
a
)
:
if
a
<
2
:
return
False
if
a
==
2
:
return
True
else
:
for
div
in
range
(
2
,
a
)
:
if
a % div
==
0
:
return
False
else
:
return
True
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