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- CRT DEFLECTION ISSUES
- =====================
- There are a some variations when it comes to FBTs and their driving
- circuits. Some TVs may even have a separated transformer to produce their
- high-voltages.
- However. Say the high-voltage for the TV's final anode is generated via the
- FBT by rectifying the (up-transformed) horizontal retrace pulses. Then, we
- can consider this arrangement as a voltage generator producing a given
- amount of kilovolts when being unloaded. This high-voltage is used to
- accelerate the beam's electrons through the tube to give them enough kinetic
- energy upon impact on the phosphor to light it up. Hence, if the electrons
- flow thought the tube, the generator gets loaded and as such its voltage
- will drop somewhat due to its internal resistance. So a high current within
- the tube (bright parts in a scene) will reduced the high-voltage of the TVs
- final anode, if its not regulated properly somehow.
- So what happens if this is the case? Basically, if the high-voltage anode of
- the TV drops, then the electrons within the tube won't be accelerated that
- much. A slower moving electron can be deviated from its path more easily and
- as such the magnetic field produced by the horizontal deflection coil will
- deflected the electron beam much more (than necessary) considering all other
- things kept equal. That's because magnetic horizontal deflection is
- inverse-proportional to sqrt(Ua), with Ua the TVs high-voltage anode. So if
- Ua drops, the beam will be deflected much more to any one side. That's to
- say; the displayed picture increases in width in bright parts of the scene.
- Funny, eh?
- But that's not the end of the story. The picture can also shrink when the
- high-voltage drops due to the generator's internal resistance. For, if the
- voltage drops due to a high beam current, the generator's driving circuity
- gets loaded. For example; say the tube's anode is at 30kV when no load is
- applied (open circuit), and say the high-voltage generator has an internal
- resistance of 6MOhms. Now if we let a beam current of 1.3mA flow through the
- tube, the generator's voltage will drop to 22.2kV loading the generators's
- driving circuit (the final transistor before the FBT etc. ) with about
- 10Watts, which is the same driving circuit producing the current for the
- horizontal deflection coil. Now if the driving circuit can't generate more
- current (limited amplification) to compensate the loss, the power to run the
- horizontal deflection coil will suffer leading to a weaker magnetic field
- not being able to fully deflect the beam to the edges. Hence, the picture
- will shrink horizontally somewhat in bright parts of the displayed scene.
- There are a lot of in-between cases here. Quite complicated if you look at
- it. However, all these issues are solved by some regulatory circuit which
- stabilizes the high-voltage keeping it constant no matter what's beam's
- current. But if this circuity starts to fail due to wear whatever, your
- picture on the screen will start to show said effects.
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