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Apr 19th, 2015
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  1. float sum1 = 0, sum2 = 0;
  2.  
  3. for (int i = 1; i < n; ++i)
  4. {
  5. sum1 += x[i] * x[i];
  6. sum2 += x[i];
  7. }
  8.  
  9. sum1 /= n;
  10. sum2 /= n;
  11.  
  12. sum2 *= sum2;
  13.  
  14. float disp = sum1 - sum2;
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