//#include "stdafx.h"
#include <iostream>

using namespace std;

int main(){
    //Блок расчета значений функции (1 подпункт задания)
    int a = 0, b = 5, k;
    long double mas[2][100], n;
    cout << "Set n"<< endl;
    cin >> n;
    for (k = 0; (k <= n || k < 100); k++){
        mas[0][k] = a + ((b - a) / n) * k;
        if (mas[0][k] >= 0 && mas[0][k] <= 1)
            mas[1][k] = -mas[0][k];
        else if (mas[0][k] > 1 && mas[0][k] < 3)
                mas[1][k] = -mas[0][k] * mas[0][k] + 5 * mas[0][k] - 5;
            else if (mas[0][k] >= 3 && mas[0][k] <= 5)
                    mas[1][k] = mas[0][k] * mas[0][k] * mas[0][k] - 26;
    }
    //Блок вывода
    for(int i = 0; i <= k; i++)
        cout << mas[0][i] << ": " << mas[1][i] << endl;
    cout << endl << endl;

    long double yk = 0, sum = 0, iter = 0, mas2[100], mas3[100];
    while (iter <= k){
        int i; // <--
        for (i = 0; i <= k; i++){
            sum += mas[1][i];
        }
        mas2[i] = ((b - a) / n) * sum;
        iter++;
    }

    for (int i = 0; i <= k-1; i++)
        mas3[i] = (mas2[i+1] - mas2[i]) / ((b - a) / n);

    long double* masOut = mas3;

    int iterEndl = 0;
    for (int i = 0; i <= k-1; i++){
            cout << " " << mas[0][i] << ": " << masOut[i] << "\t";
            iterEndl++;
        if (iterEndl == 2){
            cout << endl;
            iterEndl = 0;
        }
    }
    return 0;
}