Docmarten

/* My $http({}).then()s are all working, I am getting the exact responses/errors I want and am able to process them and spit info back out to my webpage, but now I am trying to control WHEN the $https get called. My method below, obviously isn't working.
*/

// Problem 1
var promise1 = $http({url: 'http://www.foobar.com', cache:'false'
	}).then(function(response1){
		//process response1
		return response1
	},function(response){
		//process error
	}) ;

var promise2 = $http({url: 'http://www.foobar.com', cache:'false'
	}).then(function(response2){
		//process response2
		return response2
	},function(response){
		//process error
	}) ;

/* promise1 and promise1 are executing immediately upon assignment.  Whether I want to execute them or not, they are being executed. My goal is to store the promise1/promise2 as vars or functions to then be executed within the $q.all() ;...and to execute them again when ever I want.  Even if I completely comment out the $q.all() below, the above $https are still executed as I can see the website calls being logged in the inspector/debug  */

$q.all([promise1,promise2]).then(function(response){
	for (var x=0,x<response.length;x++) {
   	//process response1 and response2
	}
	return processedResponses ;
}

/* Problem 2
Regardless of when promise1/promise2 are executed, because promise1 and promise2 are identical, I should see the same data twice in "processedResponses" - and I am. however in the inspector/debug tool I am only seeing ONE call to http://www.foobar.com when I am expecting to see two calls

Thus is promise2 not actually happening because promise1 is cached and thus response2 is simply pulled from response1???  Why am I not seeing TWO url calls to www.foobar.com??
*/