Pi Shutdown With LED

# This script will wait for a button to be pressed and then shutdown

# the Raspberry Pi.

# The button is to be connected on pin 5 (GPIO 03) and any ground

# GPIO03 is used because it can also wake from halt (hardware function)


# http://kampis-elektroecke.de/?page_id=3740
# http://raspi.tv/2013/how-to-use-interrupts-with-python-on-the-raspberry-pi-and-rpi-gpio

# https://pypi.python.org/pypi/RPi.GPIO


import RPi.GPIO as GPIO

import time

import os



# we will use the pin numbering of the SoC, so our pin numbers in the code are
# the same as the pin numbers on the gpio headers


GPIO.setmode(GPIO.BCM)


# Pin 05 (gpio03) will be input and will have his pull up resistor activated
# so we only need to connect a button to ground

GPIO.setup(03, GPIO.IN, pull_up_down = GPIO.PUD_UP)


# Pin 17 is our power pin for the LED light.  When on, the circuit completes.

GPIO.setup(17, GPIO.OUT)


# Flash the LED as the system starts up, then leave it on.

GPIO.output(17,1)

time.sleep(.25)

GPIO.output(17,0)

time.sleep(.10)

GPIO.output(17,1)

time.sleep(.25)

GPIO.output(17,0)

time.sleep(.10)

GPIO.output(17,1)

time.sleep(.25)

GPIO.output(17,0)

time.sleep(.10)

GPIO.output(17,1)




# ISR: if our button is pressed, we will have a falling edge on pin 5

# this will trigger this interrupt

:
def Int_shutdown(channel):

# flash LED on pin 17

GPIO.output(17,0)

time.sleep(.15)

 GPIO.output(17,1)

 time.sleep(.10)

  GPIO.output(17,0)

GPIO.output(17,1)

 time.sleep(.10)

time.sleep(.10)

  GPIO.output(17,0)

   GPIO.cleanup()

  # shutdown our Raspberry Pi

    os.system("sudo shutdown -h now")




# Now we are programming pin 5 as an interrupt input

# it will react on a falling edge and call our interrupt routine "Int_shutdown"


GPIO.add_event_detect(03, GPIO.FALLING, callback = Int_shutdown, bouncetime = 2000)



# do nothing while waiting for button to be pressed


while 1:
        time.sleep(1)