Advertisement
Guest User

Untitled

a guest
Jan 29th, 2015
192
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 2.86 KB | None | 0 0
  1. #include <iostream>
  2. #include <cmath>
  3. #include <algorithm>
  4. #include <vector>
  5. #include <cstring>
  6. #include <deque>
  7. #include <time.h>
  8. #include <stack>
  9. #include <stdio.h>
  10. #include <map>
  11. #include <set>
  12. #include <string>
  13. #define mp make_pair
  14. #define pb push_back
  15. #define PI 3.14159265358979323846
  16. #define MOD 1000000007
  17. typedef long long ll;
  18. using namespace std;
  19. ll n,i,j,d,x,k,y,m,l,r,sum,b[1005],rez;
  20. struct BigInt
  21. {
  22. vector <int> digits;
  23. BigInt operator + (BigInt a)
  24. {
  25. int n = max(a.digits.size(),digits.size());
  26. int i;
  27. for (i = 0; i < n; i++)
  28. {
  29. if (i > a.digits.size()-1)
  30. a.digits.push_back(0);
  31. else
  32. if (i > digits.size()-1)
  33. digits.push_back(0);
  34. }
  35. BigInt c;
  36. for (i = 0; i < n; i++)
  37. c.digits.push_back(a.digits[i]+digits[i]);
  38. for (i = 0; i < n-1; i++)
  39. {
  40. c.digits[i+1] += (c.digits[i])/10;
  41. c.digits[i] %= 10;
  42. }
  43. if (c.digits[n-1] >= 10)
  44. {
  45. c.digits.push_back(1);
  46. c.digits[n-1] %= 10;
  47. }
  48. return c;
  49. }
  50.  
  51. friend ostream& operator << (ostream& rak, BigInt& a)
  52. {
  53. int i;
  54. for (i = a.digits.size() - 1; i >= 0; i--)
  55. rak << a.digits[i];
  56. }
  57.  
  58. BigInt operator * (BigInt a)
  59. {
  60. int n = a.digits.size() + digits.size() - 1;
  61. int i,j;
  62. BigInt c;
  63. for (i = 0; i < n; i++)
  64. c.digits.push_back(0);
  65. for (i = 0; i < digits.size(); i++)
  66. for (j = 0; j < a.digits.size(); j++)
  67. c.digits[i+j] += digits[i]*a.digits[j];
  68. for (i = 0; i < n-1; i++)
  69. {
  70. c.digits[i+1] += (c.digits[i])/10;
  71. c.digits[i] %= 10;
  72. }
  73. if (c.digits[n-1] >= 10)
  74. {
  75. c.digits.push_back((c.digits[n-1])/10);
  76. c.digits[n-1] %= 10;
  77. }
  78. return c;
  79. }
  80. BigInt()
  81. {
  82. digits.clear();
  83. }
  84. BigInt(long long x)
  85. {
  86. while (x)
  87. {
  88. digits.push_back(x%10);
  89. x/=10;
  90. }
  91. }
  92. BigInt(string x)
  93. {
  94. for (int i = x.size() - 1; i >= 0; i--)
  95. {
  96. digits.push_back(x[i]-'0');
  97. }
  98. }
  99. };
  100. BigInt binpow(BigInt a, int x)
  101. {
  102. BigInt tmp;
  103. tmp.digits.push_back(1);
  104. if (x == 0)
  105. return tmp;
  106. if (x%2 == 0)
  107. {
  108. tmp = binpow(a,x/2);
  109. tmp = tmp*tmp;
  110. return tmp;
  111. } else
  112. {
  113. tmp = binpow(a,x/2);
  114. tmp = tmp*tmp;
  115. tmp = tmp*a;
  116. return tmp;
  117. }
  118. }
  119. string s;
  120. int main()
  121. {
  122. cin >> s >> n;
  123. BigInt t(s);
  124. t = binpow(t,n);
  125. cout << t;
  126. cout << endl;
  127. return 0;
  128. }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement