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  1. Tugas Akhir WAN
  2.  
  3.  
  4. Network A
  5. Network Address awal : 192.168.8.192/26
  6. Mulai dari subnet yang membutuhkan host paling banyak yaitu Green Net dengan 30 host.
  7. 2n – 2 ≥ 30 , maka n = 5 dimana 25-2 = 30 ≥ 30. Ini menandakan bahwa kita butuh 5 bit untuk host identity (192.168.8.11xxxxxx),dan sisa 3 bit ditambahkan ke network identity.
  8. Kita mendapatkan 2 subnet dari jaringan aslinya :
  9. 192.168.8.110xxxxx = 192.168.8.192/27 (Range IP Address : 192.168.8.193 s.d 192.168.8.222 , Broadcast Address:192.168.8.223).
  10. 192.168.8.111xxxxx = 192.168.8.224/27 (Range IP Address : 192.168.8.225 s.d 192.168.8.254 , Broadcast Address:192.168.8.255)
  11. Diasumsikan x = 0 , subnet mask = 255.255.255.224
  12.  
  13. Selanjutnya untuk Orange Net dengan jumlah maksimal 5 host ,kita pilih 192.168.8.224/27.
  14. 2n – 2 ≥ 5 , maka n = 3 dimana 23-2 = 6 ≥ 5. Ini menandakan bahwa kita butuh 3 bit untuk host identity (192.168.8.111xxxxx),dan sisa 5 bit ditambahkan ke network identity.
  15. 192.168.8.11100 xxx = 192.168.8.224/29 (Range IP Address : 192.168.8.225 s.d 192.168.8.230 , Broadcast Address:192.168.8.231).
  16. 192.168.8.11101xxx = 192.168.8.232/29(Range IP Address : 192.168.8.233 s.d 192.168.8.238 , Broadcast Address:192.168.8.239)
  17. 192.168.8.11110 xxx = 192.168.8.240/29 (Range IP Address : 192.168.8.241 s.d 192.168.8.246 , Broadcast Address:192.168.8.247).
  18. 192.168.8.11111xxx = 192.168.8.248/29(Range IP Address : 192.168.8.249 s.d 192.168.8.254 , Broadcast Address:192.168.8.255
  19. Diasumsikan x = 0 , subnet mask = 255.255.255.248
  20.  
  21. • Network B
  22. Network Address awal : 192.168.9.0/27
  23. Mulai dari subnet yang membutuhkan host paling banyak yaitu Net C dengan 7 host.
  24. 24 – 2 ≥ 7 , maka n = 4 dimana 24-2 = 14 ≥ 7. Ini menandakan bahwa kita butuh 4 bit untuk host identity (192.168.111.xxxxxxxx),dan sisa 4 bit ditambahkan ke network identity.
  25. Kita mendapatkan 2 subnet dari jaringan aslinya :
  26. 192.168.9.0000xxxx = 192.168.9.0/28 (Range IP Address : 192.168.9.1 s.d 192.168.9.14 , Broadcast Address:192.168.9.15).
  27. 192.168.9.0001xxxx = 192.168.9.16/28 (Range IP Address : 192.168.9.17 s.d 192.168.9.30 , Broadcast Address:192.168.9.31).
  28. 192.168.9.0010xxxx = 192.168.9.32/28 (Range IP Address : 192.168.9.33 s.d 192.168.9.46 , Broadcast Address:192.168.9.47).
  29. 192.168.9.0011xxxx = 192.168.9.48/28 (Range IP Address : 192.168.9.49 s.d 192.168.9.62 , Broadcast Address:192.168.9.63).
  30. 192.168.9.0100xxxx = 192.168.9.64/28 (Range IP Address : 192.168.9.65 s.d 192.168.9.78 , Broadcast Address:192.168.9.79).
  31. 192.168.9.0101xxxx = 192.168.9.80/28 (Range IP Address : 192.168.9.81 s.d 192.168.9.94 , Broadcast Address:192.168.9.95).
  32. 192.168.9.0110xxxx = 192.168.9.96/28 (Range IP Address : 192.168.9.97 s.d 192.168.9.110 , Broadcast Address:192.168.9.111).
  33. 192.168.9.0111xxxx = 192.168.9.112/28 (Range IP Address : 192.168.9.113 s.d 192.168.9.126 , Broadcast Address:192.168.9.127).
  34. 192.168.9.1000xxxx = 192.168.9.128/28 (Range IP Address : 192.168.9.129 s.d 192.168.9.142 , Broadcast Address:192.168.9.143).
  35. 192.168.9.1001xxxx = 192.168.9.144/28 (Range IP Address : 192.168.9.145 s.d 192.168.9.168 , Broadcast Address:192.168.9.169).
  36. 192.168.9.1010xxxx = 192.168.9.160/28 (Range IP Address : 192.168.9.161 s.d 192.168.9.174 , Broadcast Address:192.168.9.175).
  37. 192.168.9.1011xxxx = 192.168.9.176/28 (Range IP Address : 192.168.9.177 s.d 192.168.9.180 , Broadcast Address:192.168.9.181).
  38. 192.168.9.1100xxxx = 192.168.9.192/28 (Range IP Address : 192.168.9.193 s.d 192.168.9.206 , Broadcast Address:192.168.9.207).
  39. 192.168.9.1101xxxx = 192.168.9.208/28 (Range IP Address : 192.168.9.209 s.d 192.168.9.222 , Broadcast Address:192.168.9.223).
  40. 192.168.9.1110 xxxx = 192.168.9.224/28 (Range IP Address : 192.168.9.225 s.d 192.168.9.238 , Broadcast Address:192.168.9.239).
  41. 192.168.9.1111xxxx = 192.168.9.240/28 (Range IP Address : 192.168.9.241 s.d 192.168.9.254 , Broadcast Address:192.168.9.255).
  42. Diasumsikan x = 0 , subnet mask = 255.255.255.240
  43.  
  44.  
  45. Selanjutnya untuk subnet Net B dengan jumlah maksimal 5 host ,kita pilih 192.168.9.16/28.
  46. 2n – 2 ≥ 5 , maka n = 3 dimana 23-2 = 6 ≥ 5. Ini menandakan bahwa kita butuh 3 bit untuk host identity (192.168.9.0001xxxx),dan sisa 5 bit ditambahkan ke network identity.
  47. 192.168.9.00010xxx = 192.168.9.16/29 (Range IP Address : 192.168.9.17 s.d 192.168.9.22 , Broadcast Address:192.168.9.23).
  48. 192.168.8.00011xxx = 192.168.9.24/29(Range IP Address : 192.168.9.25 s.d 192.168.9.30 , Broadcast Address:192.168.9.31)
  49. Diasumsikan x = 0 , subnet mask = 255.255.255.248
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