AnonGuy's Programming Challenge [#4] - Solution

# Ruby
print "\nInput #1 -- "
inputA = gets.chomp
print "\nInput #2 -- "
inputB = gets.chomp
if inputA.downcase.delete(' ').chars.sort == inputB.downcase.delete(' ').chars.sort
    puts "\nOutput   -- \"#{inputA}\" can be formed using \"#{inputB}\"!"
else
    puts "\nOutput   -- \"#{inputA}\" cannot be formed using \"#{inputB}\"!"
end

# PHP
=begin
<?php
$a = htmlentities($_GET['a']);
$b = htmlentities($_GET['b']);

$inputA = str_replace(" ", "", strtolower($a));
$inputB = str_replace(" ", "", strtolower($b));

if(isset($a, $b))
{if(count_chars($inputA, 1)===count_chars($inputB, 1)){echo "$a can be formed using $b.";}
 else {echo "$a is can't be formed using $b.";}}
?>
=end

# JavaScript
=begin
function check(inputA, inputB)
{if (inputA.toLowerCase().replace(/[^a-z\d]/g,'').split('').sort().join('')===inputB.toLowerCase().replace(/[^a-z\d]/g,'').split('').sort().join('')){return '"'+inputA+'" can be formed using "'+inputB+'"';}
else {return '"'+inputA+'" can\'t be formed using '+inputB+'"';}}
userInputA = prompt("Input #1 ~");
userInputB = prompt("Input #2 ~");
document.write(check(userInputA, userInputB));
=end

# Python (Tonmoy Ahmed Dhrubo's Solution)
=begin
input1 = raw_input('\n1st input >> ')
input2 = raw_input('\n2nd input >> ')

string1 = input1.lower()
string2 = input2.lower()

string1 = string1.replace(' ', '')
string2 = string2.replace(' ', '')

list1 = sorted(list(string1))
list2 = sorted(list(string2))

if list1 == list2:
    print('\n[+] ((%s)) can be formed using ((%s))') % (input1, input2)
    print('\nThanks for the challenge')
    print('\nRegards , Tonmoy Ahmed Dhrubo')
else:
    print('\n[+] ((%s)) can NOT be formed using ((%s))') % (input1, input2)
    print('\nThanks for the challenge')
    print('\nRegards , Tonmoy Ahmed Dhrubo')
=end