Calculate Age after 10 Years

/*
 *  Write a program that reads your birthday from the console as text and
 *  prints how old you are now and how old you will be after 10 years.
 *  Input: 12.04.1991
 *  Output: Now: 24
 *      After 10 years: 34
 */

#include <stdio.h>
#include <time.h>

int main()
{
    int birthDay, birthMonth, birthYear;
    printf("Enter your Birth Date exactly in this format [DD.MM.YYYY]: ");
    if (scanf("%d.%d.%d", &birthDay, &birthMonth, &birthYear) == 1)
    {
        printf("Error! - Invalid input!\n");
        return 1;
    }

    time_t today = time(NULL);
    struct tm * timeNow = localtime(&today);

    int currentYear = timeNow -> tm_year + 1900;
    int currentMonth = timeNow -> tm_mon + 1;
    int currentDay = timeNow -> tm_mday;

    int age = currentYear - birthYear;

    if (birthMonth < currentMonth)
    {
        printf("Now: %d\nAfter 10 years: %d\n", age, age + 10);
    }
    else if (birthMonth == currentMonth)
    {
        if (birthDay <= currentDay)
        {
            printf("Now: %d\nAfter 10 years: %d\n", age, age + 10);
        }
        else
        {
            printf("Now: %d\nAfter 10 years: %d\n", age - 1, age + 9);
        }
    }
    else
    {
        printf("Now: %d\nAfter 10 years: %d\n", age - 1, age + 9);
    }

    return 0;
}