/*
In this problem you will compute lucky number based on person's name.
If A=1, B=2, C=3 and so on Z=26.
If we have a alphabet to digit conversion in this manner.

You need to write a C program, to take full name as
user input (preferably all in CAPS). Display substituted
digit equivalent based on the numbers you assigned before,
with spaces in between.

Iteratively calculate sum of resultant digits. If the result > 9,
calculate sum until you get a single lucky number.

Optional: You can either accept input in all CAPS or
Write logic such that you convert lower case characters to upper case.

*/

#include<stdio.h>
#include<string.h>
int main()
{
    char name[1000],Num=0,temp=0,i,j,k,p,sum=0;
    gets(name);
   // scanf("%s",name);
    // name to number conversion
    for(p=0;name[p]!='\0';p++)
    {
      for(i=1,j=65,k=97;j<=90 ;i++,j++,k++)  //check the string with ascii codes of alphabets
      {
      	if(name[p] == j || name[p] == k)
      	  {
      	  	Num= Num + i;
      	  }
      }
    }
    while(Num > 0)
    {
      while(Num != 0)
      {
        sum = sum+Num%10;
        Num=Num/10;
      }
      if(sum > 9)
      {
        Num = sum;
        sum = 0;
      }
      }
      printf("%d",sum);



	 return 0;
}